这个问题与this one有关。这次我想更进一步。给你一本字典,比如:
dd = {0: {"russell": {"score": numpy.random.rand(), "ping": numpy.random.randint(10, 100)},
"cantor": {"score": numpy.random.rand(), "ping": numpy.random.randint(10, 100)},
"godel": {"score": numpy.random.rand(), "ping": numpy.random.randint(10, 100)}},
1: {"russell": {"score": numpy.random.rand(), "ping": numpy.random.randint(10, 100)},
"cantor": {"score": numpy.random.rand(), "ping": numpy.random.randint(10, 100)},
"godel": {"score": numpy.random.rand(), "ping": numpy.random.randint(10, 100)}}}
或者像这样的列表:
ll = [{"russell": {"score": numpy.random.rand(), "ping": numpy.random.randint(10, 100)},
"cantor": {"score": numpy.random.rand(), "ping": numpy.random.randint(10, 100)},
"godel": {"score": numpy.random.rand(), "ping": numpy.random.randint(10, 100)}},
{"russell": {"score": numpy.random.rand(), "ping": numpy.random.randint(10, 100)},
"cantor": {"score": numpy.random.rand(), "ping": numpy.random.randint(10, 100)},
"godel": {"score": numpy.random.rand(), "ping": numpy.random.randint(10, 100)}}]
我想构建一个DataFrame
像:
russell godel cantor
score ping score ping score ping
0 0.17473916938994682 40 0.3443303845926545 47 0.43576522521017247 42
1 0.7341005512329682 22 0.14682222267827938 81 0.5662517436162526 59
我们可以看到列索引是MultiIndex
。有没有办法做到这一点?如果我尝试pandas.DataFrame.from_dict(dd, orient="index")
或pandas.DataFrame(ll)
,那么我得到:
russell godel cantor
0 {'score': 0.17473916938994682, 'ping': 40} {'score': 0.3443303845926545, 'ping': 47} {'score': 0.43576522521017247, 'ping': 42}
1 {'score': 0.7341005512329682, 'ping': 22} {'score': 0.14682222267827938, 'ping': 81} {'score': 0.5662517436162526, 'ping': 59}
这不是我想要的。你知道吗
现在它更复杂了,但是^{} 和^{} 、^{} 和^{} 可以帮助:
这也会起作用。请注意,嵌套的dict并不是真正嵌套的,以便于翻译。你知道吗
简而言之,用concat创建多索引df非常简单。你只需要一个数据帧字典
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