Python函数为不工作的空白条目提供默认值

Question

我想弄清楚这件事已经太久了！怎么办？你知道吗

def fallBack(submission):
    if (submission == ""):
           submission = "fixed!"  
           return(submission)

name = input("What is your name?")
(fallBack(name))

location = input("Hi "+name+"! Nice to meet you, I live inside a computer, where do you live?")

我一直有最后的输入只是打印出来什么。。。你知道吗

Answer 1

只需去掉fallBack(name)周围的括号

def fallBack(submission):
    if (submission == ""):
        submission = "fixed!"  
    return submission

name = input("What is your name?")
name = fallBack(name)

location = input("Hi "+name+"! Nice to meet you, I live inside a computer, where do you live?")

还要记住，如果使用python2.7，应该使用raw_input而不是input

Answer 2

我不知道你想做什么，但我想这样可以：

def fallBack(submission):
    if (submission == ""):
           submission = "fixed!"  
    return (submission)

name = input("What is your name?")
name = fallBack(name)

location = input("Hi "+name+"! Nice to meet you, I live inside a computer, where do you live?")

您的两个错误是在没有要修复的情况下不返回任何内容，以及不分配函数返回的值。你知道吗

顺便说一句，在Python中有一种更惯用的方法：

name = input("What is your name?")
name = name or 'fixed!'

location = input("Hi "+name+"! Nice to meet you, I live inside a computer, where do you live?")

第二行测试是否将name转换为布尔值，如果返回False（对于字符串，相当于测试它是否不是空的），则将其替换为'fixed!'

Answer 3

您需要存储fallBack()的结果。 另外，更改fallBack()以返回非空的原始值：

def fallBack(submission):
    if not submission:
        return "fixed!"
    else:
        return submission

然后，像这样使用：

name = fallBack(input("What is your name?"))