我是否能够使用函数“count（）”来查找密码中大写字母的数量(（Python）

Question

当我输入下面的代码时，它说：

TypeError: must be str, not list

这是不是意味着我不能使用count（）函数，或者有其他方法可以编程

password = "CheeseMakesMeHappy"
uppercase =["A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"]
print (password.count(uppercase))

Answer 1

只需检查密码中的每个字符，并检查它是否是大写字符。 例如：

password = "FoOoObA"
print(len([c for c in password if c.isupper()]))
>> 4

另一种方法是使用集合和位掩码来计算唯一大写字符的数量

password = "CheeseMakesMeHappy"
uppercase = set(["A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"])
print(len(set(password)&uppercase))
>> 3

然而，set解决方案将只计算唯一字符，但是在密码强度度量的情况下，这可能不是一个坏主意

Answer 2

问题是方法count()需要一个string对象。现在，使用这一行(password.count(uppercase))，可以有效地将数组对象传递给函数。请参阅zeraien的答案以获得一个好的解决方案