基于第三个lis返回的索引，从两个列表中创建一个新列表

Question

假设我有以下列表（Python3）：

numbers = [1,2,3,4,5,6]
letters = [a,b,a,b,c,c]
state = [False, False, False, False, False, False]

我要做的是从用户那里接收两个在列表字母长度范围内的索引位置的输入。如果他的选择对应于匹配的字母，例如a和a（索引0和2），那么对于所述位置，列表状态必须从False更改为True。之后，它应该根据新的状态列表创建一个新列表，如果状态中的元素为False，则从数字中获取索引项，如果状态为true，则从列表字母中获取索引项：

choice = 0
choice_2 = 2
if letters[choice] == letters[choice_2]:
   change state[choice] and state[choice_2] to True
create fourth list from list state and use values from numbers and letters
For i in range(len(state)):
    if state[i] == True:
       element in index[i] of list letters is used
    else:
       element in index[i] of list numbers is used

创建新列表，以便：

new_list = [a,2,a,4,5,6]

Answer 1

numbers = [1,2,3,4,5,6]
letters = ["a","b","a","b","c","c"]
state = [False, False, False, False, False, False]


choice1 = input("Enter Your 1st choice: ")
choice2 = input("Enter Your 2nd choice: ")

if letters[choice1] == letters[choice2]:
    state[choice1] = (not state[choice1])
    state[choice2] = (not state[choice2])

List = []

print state
for i in range(len(state)):
    if state[i] == True:
        List.append(letters[i])
    else:
        List.append(numbers[i])

print List

输入：

Enter Your 1st choice: 0
Enter Your 1st choice: 2

输出：

['a', 2, 'a', 4, 5, 6]