停止线程Python

Question

我有这段代码，我怎么能阻止func2和func1？像Thread(target = func1).stop()这样的东西不起作用

import threading
from threading import Thread

def func1():
    while True:
        print 'working 1'

def func2():
    while True:
        print 'Working2'

if __name__ == '__main__':
    Thread(target = func1).start()
    Thread(target = func2).start()

Answer 1

最好使用消息队列来让其他线程停止。

import time
import threading
from threading import Thread
import Queue

q = Queue.Queue()

def func1():
    while True:
        try:
            item = q.get(True, 1)
            if item == 'quit':
                print 'quitting'
                break
        except:
            pass
        print 'working 1'

def func2():
    time.sleep(10)
    q.put("quit")
    while True:
        time.sleep(1)
        print 'Working2'

if __name__ == '__main__':
    Thread(target = func1).start()
    Thread(target = func2).start()

Answer 2

不能告诉线程停止，必须使其在目标函数中返回

from threading import Thread
import Queue

q = Queue.Queue()

def thread_func():
    while True:
        # checking if done
        try:
            item = q.get(False)
            if item == 'stop':
                break  # or return
        except Queue.Empty:
            pass
        print 'working 1'


def stop():
    q.put('stop')


if __name__ == '__main__':
    Thread(target=thread_func).start()

    # so some stuff
    ...
    stop()  # here you tell your thread to stop
            # it will stop the next time it passes at (checking if done)