In [55]: np.sqrt(np.nansum(np.square(x)))
Out[55]: 3.7416573867739413
y是规范化数组:
In [56]: y = x / np.sqrt(np.nansum(np.square(x)))
In [57]: y
Out[57]: array([ 0.26726124, 0.53452248, nan, 0.80178373])
In [58]: np.linalg.norm(y[~np.isnan(y)])
Out[58]: 1.0
import numpy as np
a = np.random.rand(10) # Generate random data.
a = np.where(a > 0.8, np.nan, a) # Set all data larger than 0.8 to NaN
a = np.ma.array(a, mask=np.isnan(a)) # Use a mask to mark the NaNs
a_norm = a / np.sum(a) # The sum function ignores the masked values.
a_norm2 = a / np.std(a) # The std function ignores the masked values.
可以使用^{} 计算范数并忽略nan:
下面是忽略
nan
的规范:y
是规范化数组:可以使用
numpy.ma.array
函数屏蔽数组,然后应用任何numpy
操作:您仍然可以访问原始数据:
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