擅长:python、mysql、java
<p>既然这个问题还没有解决,我就把它写成:</p>
<pre><code>import os
items = []
s1 = 's3://{Name}/{{Key}}'.format(**response)
for i in response['Contents']:
v1 = s1.format(name,**i)
v2 = os.path.basename(i['Key'])
v3 = i['Size']
items.append([v1,v2,v3])
</code></pre>