如果elif条件不工作，Python请求响应

Question

您好，我在if-else json响应上的代码有问题，我很确定我的方法是正确的，但是代码在else语句上没有继续

import requests
import psycopg2
        conn = psycopg2.connect(dbname='databasename',user='postgres',password='12345',host='x.x.x.x', port='xxxx') # works correctly
        print('success db')
        cur = conn.cursor()

        cur.execute("SELECT mobile_number FROM users WHERE status='ACTIVE'") # this is my query 
        conn.commit();
        row_count = cur.rowcount
        print('This is the number of rows: ', row_count)
        result = [mobileNum[0] for mobileNum in cur.fetchall()]

        for mobileNum in result:
            print('Current Number: ', mobileNum)
            pushnotif = push_notif(mobileNum) # This is a function for http request
            
            if pushnotif['success'] == 1 and pushnotif['failure'] == 0 : # This line of code is working and continue the for loop
                print('Success!!!')
            elif pushnotif['success'] == 0 and pushnotif['failure'] == 1: # This line of code is working but only when I'm printing a sentence like faileedddd!
                print(pushnotif['results']['error']) # This doesn't print the result error on http response and exits the for loop
            elif pushnotif['message'] == "Invalid number": # This line doesn't work and end the for loops
                print(pushnotif['message'])
            else: # The code doesn't go here whenever the response is not 200 OK or push_notif['message'] or push_notif['results''error']
                print('error')

以下是回应的样本：

{
    "multicast_id": xxx,
    "success": 1,
    "failure": 0,
    "canonical_ids": 0,
    "results": [
        {
            "message_id": "xxx"
        }
    ]
}

或

{
    "multicast_id": xxxx,
    "success": 0,
    "failure": 1,
    "canonical_ids": 0,
    "results": [
        {
            "error": "invalid"
        }
    ]
}

或

{
    "message": "Invalid number"
}

Answer 1

pushnotif = push_notif(mobileNum)
pushlen = len(pushnotif)

if pushlen == 5:
     print("This will print if API response is equal to 5", pushnotif)
elif pushlen == 1:
     print("This will print if API response is equal to 1", pushnotif)
else:
     print("This will print unexpected response", pushnotif)

这就是逻辑再次谢谢你

Answer 2

比如说，你最初得到的回答如下

{
    "message": "Invalid number"
}

在这里，您的字典只有一个名为message的键。因此，当您使用success、failure等键检查响应时，您的程序将停止执行，因为这些键不在当前响应中，并且永远不会执行else语句

Answer 3

我不确定函数push_notif返回什么，但是如果它返回一个常规的dict，这可能是一个问题，因为您假设键(success, failure and result)存在于dict中，而您提供的上一个响应示例并非如此。因此，通常情况下，异常会引发并停止程序，或者至少在捕获时，结束for循环并退出函数