如何在python中将一段文本修剪成完整的句子

Question

我有一段文字不是完整的句子。比如说

reased 11%. Search advertising revenue, excluding traffic acquisition costs, was relatively unchanged. Indus

完整的句子是

... increased 11%. Search advertising revenue, excluding traffic acquisition costs, was relatively unchanged. Industry ...

我想要的是，如果句子被切掉，比如... increased 11%和Industry...，那么我放弃它们，只返回完整的句子Search advertising revenue, excluding traffic acquisition costs, was relatively unchanged.

我可以用nltk或spacy来做吗

更新

对不起，我在原来的帖子里没有把我的问题说清楚

可能有不同的情况：

• Hey! How are you? Good!应返回Hey! How are you? Good!

• ...ey. How are you? I am good. How about....应返回How are you? I am good.

我不知道课文中有多少完整的句子

Answer 1

您可以使用spacy获得字符串中的所有句子，例如

import spacy
nlp = spacy.load("en_core_web_sm")
doc = nlp("I am good. How are you? Thank you.")
for sent in doc.sents:
    print(sent)

sents属性包含字符串中的所有句子

Output：

I am good.
How are you?
Thank you.

对于使用

... increased by 11%. Search advertising revenue, excluding traffic acquisition costs, was relatively unchanged. Industry ...

如果只获得完整的句子，只需将doc.sents放在list()方法中，并使用索引访问它。e、 g

doc = nlp("... increased 11%. Search advertising revenue, excluding traffic acquisition costs, was relatively unchanged. Industry ...")
print(list(doc.sents)[1])

输出：

Search advertising revenue, excluding traffic acquisition costs, was relatively unchanged.