我正在使用Giphy API，我想知道如何自动获取GIF图像URL，而不是手动获取

Question

这是我的代码，它工作得很好，但是我如何才能使它有一个新的变量，它等于GIF的图像URL，这样用户就可以获得GIF的源URL

import requests

url = "https://giphy.p.rapidapi.com/v1/gifs/search"

searchtag = input()

querystring = {"api_key":"secret_key","q":searchtag,"limit":"1","offset":"0","rating":"pg-13"}

headers = {
    'x-rapidapi-key': "4005b98f9bmsh977c629b89034a7p19b52fjsn22b7fb5ce3bb",
    'x-rapidapi-host': "giphy.p.rapidapi.com"
    }

response = requests.request("GET", url, headers=headers, params=querystring)

print(response.text)

Answer 1

首先，为了您自己的人身安全，您可能应该删除api密钥。我建议查看环境文件以存储不属于数据库的私人信息。第二步，回答您的问题，如果您有任何想法，可以将url声明为变量，如下所示：

    import requests

url = "https://giphy.p.rapidapi.com/v1/gifs/search"

searchtag = input()

querystring = {"api_key":process.env.APIKEY,"q":searchtag,"limit":"1","offset":"0","rating":"pg-13"}

headers = {
    'x-rapidapi-key': "4005b98f9bmsh977c629b89034a7p19b52fjsn22b7fb5ce3bb",
    'x-rapidapi-host': "giphy.p.rapidapi.com"
    }

response = requests.request("GET", url, headers=headers, params=querystring)
gifurl = response.text
print(gifurl)