无法摆脱由BeautifulSoup引起的适航性问题

Question

我已经用python和BeautifulSoup组合编写了一个脚本来解析网页中的某个地址。然而，当我运行下面的脚本时，当它到达第address = [item.find_next_sibling().get_text(strip=True)行时，我得到了一个问题AttributeError: 'NavigableString' object has no attribute 'text'。我可以摆脱这个问题，如果我尝试注释掉的行。不过，我想坚持目前的应用方式。我能做什么？你知道吗

这是我的尝试：

import requests
from bs4 import BeautifulSoup

URL = "https://beta.companieshouse.gov.uk/officers/lX9snXUPL09h7ljtMYLdZU9LmOo/appointments"

def fetch_names(session,link):
    session.headers = {"User-Agent":"Mozilla/5.0"}
    res = session.get(link)
    soup = BeautifulSoup(res.text,"lxml")
    for items in soup.select("#content-container dt"):

        #the error appears in the following line

        address = [item.find_next_sibling().get_text(strip=True) for item in items if "correspondence address" in item.text.lower()][0]
        print(address)

if __name__ == '__main__':
    with requests.Session() as session:
        fetch_names(session,URL)

我可以通过下面这样的操作来消除错误，但我想坚持我在脚本中尝试的方式：

items = soup.select("#content-container dt")
address = [item.find_next_sibling().get_text(strip=True) for item in items if "correspondence address" in item.text.lower()][0]
print(address)

EDIT:

It's not an answer but this is how I tried to play around (still unsure how to apply .find_previous_sibling() though:

import requests
from bs4 import BeautifulSoup

URL = "https://beta.companieshouse.gov.uk/officers/lX9snXUPL09h7ljtMYLdZU9LmOo/appointments"

def fetch_names(session,link):
    session.headers = {"User-Agent":"Mozilla/5.0"}
    res = session.get(link)
    soup = BeautifulSoup(res.text,"lxml")
    for items in soup.select("#content-container dt"):
        address = [item for item in items.strings if "correspondence address" in item.lower()]
        print(address)

if __name__ == '__main__':
    with requests.Session() as session:
        fetch_names(session,URL)

它产生（无导航问题）。你知道吗

[]
['Correspondence address']
[]
[]

Answer 1

items不是节点列表，而是单个节点，因此您不应该在这里将其用作迭代器-for item in items。只需将列表替换为以下内容：

for items in soup.select("#content-container dt"):
    if "correspondence address" in items.text.lower():
        address = items.find_next_sibling().get_text(strip=True)
        print(address)