使用简单代码获取csv fi中整列的平均值(用Python)

2024-03-27 15:41:52 发布

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我见过类似的问题,但从来没有一个简单明了的Python答案。你知道吗

我只是想得到csv文件中“high”列的平均值。你知道吗

import csv
import numpy as np    


with open('2010-Jan-June.csv', 'r', encoding='utf8', newline='') as f:
    highs = []
    for row in csv.DictReader(f, delimiter=','):
        high = int(row['high'])
print(sum(highs)/len(highs))

我的csv如下所示:

date,high,low,precip
1-Jan,43,41,0
2-Jan,50,25,0
3-Jan,51,25,0
4-Jan,44,25,0
5-Jan,36,21,0
6-Jan,39,20,0
7-Jan,47,21,0.04
8-Jan,30,14,0
9-Jan,30,12,0

Tags: 文件csv答案importnumpyaswithnp
3条回答

既然您导入了numpy,您就可以像pandas一样轻松地使用它:

从样本的粘贴副本中读取:

In [36]: txt="""date,high,low,precip
    ...: 1-Jan,43,41,0
    ...: 2-Jan,50,25,0
    ...: 3-Jan,51,25,0
    ...: 4-Jan,44,25,0
    ...: 5-Jan,36,21,0
    ...: 6-Jan,39,20,0
    ...: 7-Jan,47,21,0.04
    ...: 8-Jan,30,14,0
    ...: 9-Jan,30,12,0"""

numpy 1.14的Python3喜欢使用encoding参数:

In [38]: data = np.genfromtxt(txt.splitlines(),delimiter=',',dtype=None,names=True,
    ...: encoding=None)
In [39]: data
Out[39]: 
array([('1-Jan', 43, 41, 0.  ), ('2-Jan', 50, 25, 0.  ),
       ('3-Jan', 51, 25, 0.  ), ('4-Jan', 44, 25, 0.  ),
       ('5-Jan', 36, 21, 0.  ), ('6-Jan', 39, 20, 0.  ),
       ('7-Jan', 47, 21, 0.04), ('8-Jan', 30, 14, 0.  ),
       ('9-Jan', 30, 12, 0.  )],
      dtype=[('date', '<U5'), ('high', '<i8'), ('low', '<i8'), ('precip', '<f8')])

结果是一个结构化数组,从中很容易选择high字段:

In [40]: data['high']
Out[40]: array([43, 50, 51, 44, 36, 39, 47, 30, 30])
In [41]: data['high'].mean()
Out[41]: 41.111111111111114

或者在一行中,只加载一列:

In [44]: np.genfromtxt(txt.splitlines(),delimiter=',',skip_header=1,usecols=[1]).mean()
Out[44]: 41.111111111111114

使用熊猫:

import pandas as pd

avg = pd.read_csv(r'/path/to/2010-Jan-June.csv', usecols=['high'], squeeze=True).mean()

注意,使用纯Python完全可以做到这一点:

import csv
import statistics as stats

with open('2010-Jan-June.csv') as f:
    avg = stats.mean(row['high'] for row in csv.DictReader(f, delimiter=','))

print(avg)

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