在SQLAlchemy中防止多对多关系中的重复表条目
我正在尝试使用SQLAlchemy建立一个电影数据库,这里有一个多对多的关系。我有两个表,一个是'movie'(电影),另一个是'actor'(演员),还有一个关联表'movie_actor'。我希望能够向电影表中添加一部新电影,但如果这部新电影中的某些演员已经在演员表中存在,我希望能避免在演员表中重复添加他们,同时仍然将电影ID和演员ID添加到关联表中。以下是我的表结构:
from sqlalchemy import Table, Column, Integer, String, ForeignKey, create_engine, and_, or_
from sqlalchemy.ext.declarative import declarative_base
from sqlalchemy.orm import backref, mapper, relationship, Session
Base = declarative_base()
formats = {'1': 'DVD', '2': 'Blu-ray', '3': 'Digital', '4': 'VHS'}
###########################################################################################
class Movie(Base):
"""Movie Class"""
__tablename__ = "movie"
movie_id = Column(Integer, primary_key=True)
title = Column(String(20), nullable=False, unique=True)
year = Column(Integer, nullable=False)
format = Column(String, nullable=False)
movie_actor = relationship("MovieActor", cascade="all, delete-orphan", backref="movie")
def __init__(self, title, year, format):
self.title = title
self.year = year
self.format = format
def __repr__(self):
return "%s %s" % (self.movie_id, self.title)
###########################################################################################
class Actor(Base):
"""Actor Class"""
__tablename__ = "actor"
actor_id = Column(Integer, primary_key=True)
full_name = Column(String(30), nullable=False, unique=True)
def __init__(self, full_name):
self.full_name = full_name
def __repr__(self):
return "%s %s" % (self.actor_id, self.full_name)
###########################################################################################
class MovieActor(Base):
"""MovieActor Association Class"""
__tablename__ = "movieactor"
movie_id = Column(Integer, ForeignKey('movie.movie_id'), primary_key=True)
actor_id = Column(Integer, ForeignKey('actor.actor_id'), primary_key=True)
def __init__(self, actor):
self.actor = actor
actor = relationship(Actor, lazy='joined')
def __repr__(self):
return "%s, %s" % (self.movie_id, self.actor_id)
接下来是一个处理插入新记录和查询数据库的类:
###########################################################################################
class Database(object):
# A connection to the movie database is established upon instantiation.
def __init__(self):
engine = create_engine('sqlite:///bmdb.db')
Base.metadata.create_all(engine)
session = Session(engine)
self.session = session
# add_new method takes a dictionary of strings containing all the info for a new movie: "title, year, format, actors"
# and formats the strings, then adds them to the proper tables in the database
def add_new(self, new_movie):
#find out what formats exist
format = ""
for i in range(1,5):
try:
format += new_movie[formats[str(i)]]
format += ", "
except:
pass
format = format[:-1]
format = format[:-1]
# capitalize the first letter of each word in the movie title
title = " ".join(word[0].upper() + word[1:].lower() for word in new_movie['title'].split())
try:
movie = Movie(title, new_movie['year'], format)
# add the new movie to the session
self.session.add(movie)
# commit the new movie to the database
self.session.commit()
except:
print "Duplicate Movie"
self.session.rollback()
return
# parse the text in the actors entry
# take the incoming string of all actors in the movie and split it into a list of individual actors
actors = new_movie['actors'].split(", ")
for i in range(len(actors)):
# for each actor in the list, capitalize the first letter in their first and last names
actors[i] = " ".join(word[0].upper() + word[1:].lower() for word in actors[i].split())
# add each formatted actor name to the Actor table
actor = Actor(actors[i])
try:
# add the appropriate association between the movie and the actors to the MovieActor table
movie.movie_actor.append(MovieActor(actor))
# add the new actor and movieactor association to the session
self.session.add(movie)
self.session.commit()
except:
print "Duplicate Actor"
self.session.rollback()
目前我的代码中,在add_new()方法里的try/except块可以防止重复的演员被添加到数据库,因为演员表中的'full_name'列被设置为唯一(unique=True),但这也导致无法向movie_actor关联表中添加记录。
简单来说,我想知道的是如何添加一部电影,检查这部电影中的演员是否已经存在于演员表中,如果存在,就不把这些演员插入演员表,而是从演员表中获取他们已有的演员ID,并在movie_actor关联表中创建相应的关联。
1 个回答
2
你可能需要在你的 try:
代码块里插入一个 self.session.begin_nested()
。这样,如果因为重复的键值需要回滚操作,你仍然可以把演员添加到电影里。
from sqlalchemy.exc import IntegrityError # only catch the right exception!
# in for loop:
try:
session.begin_nested()
actor = Actor(actors[i])
except IntegrityError:
print "Duplicate Actor"
self.session.rollback() # subtransaction
actor = self.session.query(Actor).\
filter(Actor.name==actors[i]).first()
else:
self.session.commit() # subtransaction
# add the appropriate association between the movie and the actors to the MovieActor table
movie.movie_actor.append(MovieActor(actor))
# add the new actor and movieactor association to the session
self.session.add(movie)
self.session.commit()
补充:在处理重复键值错误时,记得要捕获 IntegrityError
这个错误。