如何从嵌套字典中获取单个项

Question

我正在从一个文件中读取数据，数据大概是这样的：

{"day" :"Monday", "alarm":"on", "kids":"School" , "work":"days"}
{"day" :"Tuesday", "alarm":"on", "kids":"School" , "work":"days"}
{"day" :"Wednesday", "alarm":"on", "kids":"School" , "work":"days"}
{"day" :"Thursday", "alarm":"on", "kids":"School" , "work":"nights"}
{"day" :"Friday", "alarm":"on", "kids":"School" , "work":"nights"}
{"day" :"Saturday", "alarm":"off", "kids":"Dance" , "work":"overtime"}
{"day" :"Sunday", "alarm":"off", "kids":"Soccer" , "work":"off"}

我把这些数据放进一个字典里，然后根据一些条件来检查这个字典，最后把这个字典放进另一个字典里，像这样：

import ast
o=open('schedule.txt','rb')
day_={}
for lines in o:
    dict_={}
    dict_= ast.literal_eval(lines)
    if dict_['day']=='Monday':
        day_['1']=dict_.items()
    elif dict_['day']=='Tuesday':
        day_['2']=dict_.items()
    elif dict_['day']=='Wednesday':
        day_['3']=dict_.items()
    elif dict_['day']=='Thursday':
        day_['4']=dict_.items()
    elif dict_['day']=='Friday':
        day_['5']=dict_.items()
    elif dict_['day']=='Saturday':
        day_['6']=dict_.items()
    elif dict_['day']=='Sunday':
        day_['7']=dict_.items()
    else:
        print('there was an error')
o.close()
print day_.items()
#this seems to work properly

现在如果我只想知道孩子们在第4天做了什么，我该怎么做呢？或者有没有更简单的方法来在程序中保存这些数据，以便将来使用？

Answer 1

你可以通过使用字典来简化你的代码，把星期几的名字和数字对应起来。比如，如果你想提取第4天的"kids"这个项目，你可以用result[4]["kids"]来实现：

days = {"Monday": 1, "Tuesday": 2, "Wednesday": 3, "Thursday": 4,
        "Friday": 5, "Saturday": 6, "Sunday": 7}
result = {}
with open('schedule.txt', 'rb') as f:
    for line in f:
        d = ast.literal_eval(line)
        result[days[d["day"]]] = d
print result[4]["kids"]