创建数据库连接并在多个进程中维护

26 投票
1 回答
16366 浏览
提问于 2025-04-17 03:06

这段内容和我之前发的一个帖子有点相似,主要是对那个帖子进行回应,同时也提出了一个新问题。

简单回顾一下:我需要更新一个空间数据库里的每一条记录,这个数据库里有一些点的数据集,这些点的数据集覆盖了一些多边形的数据集。对于每一个点,我想给它分配一个键,以便把它和它所在的多边形关联起来。比如说,如果我的点“纽约市”在多边形“美国”里面,而这个“美国”多边形的标识是‘GID = 1’,那么我就会给我的点“纽约市”分配‘gid_fkey = 1’。

好的,这个目标已经通过多进程实现了。我发现使用这种方法速度提高了150%,所以确实有效。但我觉得这样做有很多不必要的开销,因为每条记录都需要一个数据库连接。

下面是代码:

import multiprocessing, time, psycopg2

class Consumer(multiprocessing.Process):

    def __init__(self, task_queue, result_queue):
        multiprocessing.Process.__init__(self)
        self.task_queue = task_queue
        self.result_queue = result_queue

    def run(self):
        proc_name = self.name
        while True:
            next_task = self.task_queue.get()
            if next_task is None:
                print 'Tasks Complete'
                self.task_queue.task_done()
                break            
            answer = next_task()
            self.task_queue.task_done()
            self.result_queue.put(answer)
        return


class Task(object):
    def __init__(self, a):
        self.a = a

    def __call__(self):        
        pyConn = psycopg2.connect("dbname='geobase_1' host = 'localhost'")
        pyConn.set_isolation_level(0)
        pyCursor1 = pyConn.cursor()

        procQuery = 'UPDATE city SET gid_fkey = gid FROM country  WHERE ST_within((SELECT the_geom FROM city WHERE city_id = %s), country.the_geom) AND city_id = %s' % (self.a, self.a)

        pyCursor1.execute(procQuery)
        print 'What is self?'
        print self.a

        return self.a

    def __str__(self):
        return 'ARC'
    def run(self):
        print 'IN'

if __name__ == '__main__':
    tasks = multiprocessing.JoinableQueue()
    results = multiprocessing.Queue()

    num_consumers = multiprocessing.cpu_count() * 2
    consumers = [Consumer(tasks, results) for i in xrange(num_consumers)]
    for w in consumers:
        w.start()

    pyConnX = psycopg2.connect("dbname='geobase_1' host = 'localhost'")
    pyConnX.set_isolation_level(0)
    pyCursorX = pyConnX.cursor()

    pyCursorX.execute('SELECT count(*) FROM cities WHERE gid_fkey IS NULL')    
    temp = pyCursorX.fetchall()    
    num_job = temp[0]
    num_jobs = num_job[0]

    pyCursorX.execute('SELECT city_id FROM city WHERE gid_fkey IS NULL')    
    cityIdListTuple = pyCursorX.fetchall()    

    cityIdListList = []

    for x in cityIdListTuple:
        cityIdList.append(x[0])


    for i in xrange(num_jobs):
        tasks.put(Task(cityIdList[i - 1]))

    for i in xrange(num_consumers):
        tasks.put(None)

    while num_jobs:
        result = results.get()
        print result
        num_jobs -= 1

根据我用'time'模块测量的结果,每个连接的时间大约在0.3到1.5秒之间。

有没有办法让每个进程只建立一个数据库连接,然后把city_id的信息作为变量传入查询中呢?这样我可以创建四个进程,每个进程都有一个数据库连接,然后把city_id传进去进行处理。

1 个回答

43

试着把连接的创建放在消费者的构造函数里,然后把它传给执行的任务:

import multiprocessing, time, psycopg2

class Consumer(multiprocessing.Process):

    def __init__(self, task_queue, result_queue):
        multiprocessing.Process.__init__(self)
        self.task_queue = task_queue
        self.result_queue = result_queue
        self.pyConn = psycopg2.connect("dbname='geobase_1' host = 'localhost'")
        self.pyConn.set_isolation_level(0)


    def run(self):
        proc_name = self.name
        while True:
            next_task = self.task_queue.get()
            if next_task is None:
                print 'Tasks Complete'
                self.task_queue.task_done()
                break            
            answer = next_task(connection=self.pyConn)
            self.task_queue.task_done()
            self.result_queue.put(answer)
        return


class Task(object):
    def __init__(self, a):
        self.a = a

    def __call__(self, connection=None):        
        pyConn = connection
        pyCursor1 = pyConn.cursor()

        procQuery = 'UPDATE city SET gid_fkey = gid FROM country  WHERE ST_within((SELECT the_geom FROM city WHERE city_id = %s), country.the_geom) AND city_id = %s' % (self.a, self.a)

        pyCursor1.execute(procQuery)
        print 'What is self?'
        print self.a

        return self.a

    def __str__(self):
        return 'ARC'
    def run(self):
        print 'IN'

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