Python使用ctypes处理dll - 结构体输出参数
在这个dll的头文件里,我有一个这样的结构:
typedef struct USMC_Devices_st{
DWORD NOD; // Number of the devices ready to work
char **Serial; // Array of 16 byte ASCII strings
char **Version; // Array of 4 byte ASCII strings
} USMC_Devices; // Structure representing connected devices
我想调用一个dll里的函数:
DWORD USMC_Init( USMC_Devices &Str );我试着这样做:
class USMCDevices(Structure):
_fields_ = [("NOD", c_long),
("Serial", c_char_p),
("Version", c_char_p)]
usmc = cdll.USMCDLL #this is the dll file
init = usmc.USMC_Init
init.restype = c_int32; # return type
init.argtypes = [USMCDevices]; # argument
dev = USMCDevices()
init(dev)
但是这里出现了一个错误。我猜问题出在“Serial”和“Version”这两个数组上,它们的大小是和设备数量(NOD)对应的。
有没有什么办法可以解决这个问题呢?
非常感谢你的帮助!!!
1 个回答
2
对于 char **
指针,使用 POINTER(c_char_p)
。当你对 Serial
或 Version
进行索引时,会为给定的以空字符结尾的字符串创建一个 Python 字符串。请注意,如果你在数组中索引超过 NOD - 1
,要么会得到一些无效的值,要么会导致解释器崩溃。
C:
#include <windows.h>
typedef struct USMC_Devices_st {
DWORD NOD; // Number of the devices ready to work
char **Serial; // Array of 16 byte ASCII strings
char **Version; // Array of 4 byte ASCII strings
} USMC_Devices;
char *Serial[] = {"000000000000001", "000000000000002"};
char *Version[] = {"001", "002"};
__declspec(dllexport) DWORD USMC_Init(USMC_Devices *devices) {
devices->NOD = 2;
devices->Serial = Serial;
devices->Version = Version;
return 0;
}
// build: cl usmcdll.c /LD
Python:
import ctypes
from ctypes import wintypes
class USMCDevices(ctypes.Structure):
_fields_ = [("NOD", wintypes.DWORD),
("Serial", ctypes.POINTER(ctypes.c_char_p)),
("Version", ctypes.POINTER(ctypes.c_char_p))]
usmc = ctypes.cdll.USMCDLL
init = usmc.USMC_Init
init.restype = wintypes.DWORD
init.argtypes = [ctypes.POINTER(USMCDevices)]
dev = USMCDevices()
init(ctypes.byref(dev))
devices = [dev.Serial[i] + b':' + dev.Version[i]
for i in range(dev.NOD)]
print('\n'.join(d.decode('ascii') for d in devices))
输出:
000000000000001:001
000000000000002:002