在networkx中为边上色

Question

我写了一段简单的代码，用来在一个给定的图G中生成随机漫步，使用的是networkx库。现在，当我在图中漫步时，我想用matplotlib把边缘上色并绘制出来，比如在一个循环中。举个例子：假设我从节点1走到节点2，沿着一条连接的边，我希望那条边的颜色和其他边不一样。以下是代码：

def unweighted_random_walk(starting_point,ending_point, graph):
'''
starting_point: String that represents the starting point in the graph
ending_point: String that represents the ending point in the graph
graph: A NetworkX Graph object
'''
##Begin the random walk
current_point=starting_point
#current_node=graph[current_point]
current_point_neighors=graph.neighbors(current_point)
hitting_time=0

#Determine the hitting time to get to an arbitrary neighbor of the
#starting point
while current_point!=ending_point:
    #pick one of the edges out of the starting_node with equal probs
    possible_destination=current_point_neighbors[random.randint(0,current_point_neighors)]
    current_point=possible_destination
    current_point_neighbors=graph.neighbors(current_point)
    hitting_time+=1
return hitting_time

Answer 1

这个方法很好用……不过，要注意把列表填充上合适的值。下面是一个可以正常工作的代码修改：

def colors(G, attrib):
   colors = []    
   for node,data in G.nodes_iter(data=True):
     # return a color string based on whatever property you want
     if data['someproperty'] != attrib:
        colors.append('AliceBlue')
     else:
        colors.append('Crimson')
   return colors

Answer 2

这是我使用的内容：

def colors(G):
    colors = []
    for edge,data in G.edges_iter(data=True):
        # return a color string based on whatever property you want
        return 'red' if data['someproperty'] else 'blue'

        # alternatively you could store a 'color' key on the edge
        # return data['color']

    return colors

# When you invoke the draw command pass a list of edge colors
nx.draw_spectral(G, edge_color=colors(G))