Java中用字符替换字符对的循环

Question

所以我想把有字符对的字符串变成一个字符串，把所有相同的字符对变成一个字母。就像我有一根弦：“325A 5A 65755A 67” 改为“ABBCDBE”（32=A，5A=B，65=C，75=D，67=E）。我有这个剧本：

public static void main(String[] args) {
    String viesti;
    viesti = "23 44 B0 9A 61 A4 91 12 47 A4 91 96 44 B0 BF E0 32 68 EC 96 BF 32 44 B0 CA 32 35 A4 BF 32 EC A4 61 E4 CA 61 5A 32 70 12 91 32 BC 44 12 32 9A 44 91 32 96 91 E0 32 BA CA 61 BC 32 35 CA 47 47 32 E4 44 B0 CA 32 A1 CA 47 47 44 35 32 EC A4 E8 0A CA 61 E0 32 68 EC CA 32 82 61 44 70 47 CA 52 32 35 96 91 EC 32 91 EC 96 BF 32 E8 96 82 EC CA 61 32 96 BF 32 91 EC A4 91 32 91 EC CA 32 0A CA BC 32 96 BF 32 82 61 CA 91 91 BC 32 47 44 B0 9A E0 32 20 32 35 96 47 47 32 E8 44 52 CA 32 12 82 32 35 96 91 EC 32 A4 32 70 CA 91 91 CA 61 32 CA B0 E8 61 BC 82 91 96 44 B0 32 BF EC CA 52 CA 32 A4 B0 BC 32 BF 44 44 B0 E0 32 03 44 12 61 32 BF 44 47 12 91 96 44 B0 32 96 BF 5E 32 96 9A CA 47 47 E4 E8 A1 9A 61 A1 61 E0";
    int pituus;
    pituus = viesti.length();
    int i;
    i=1;
    char luku;
    char luku2;
    char merkki;
    String hexa;
    String merkki2;
    String viesti2;
    StringBuilder sb = new StringBuilder();
    merkki = 'A';
    while(i < pituus){
    luku = viesti.charAt(i-1);
    luku2 = viesti.charAt(i);
    if(luku2!=' ' && merkki!=(char)91){
        sb.append(luku);
        sb.append(luku2);
        hexa = sb.toString();
        sb.setLength(0);
        merkki2 = Character.toString(merkki);
        viesti2 = viesti.replace(hexa,merkki2);
          i+=3;  
          merkki++;
    }
    else {
        i+=2;
    }
    }
System.out.print(viesti2);
}
}

但似乎viesti2只更换了第一对，其他什么都没有。如何解决这个问题

Answer 1

我猜这些字符对是十六进制数吧

// Separate the pairs into array elements
String[] pairs = viesti.split(" ");
Map<Integer, Character> codeMap = new HashMap<Integer, Character>();
char[] result = new char[pairs.length];
char curChar = 'A';
// Iterate over the pairs
for (int i = 0; i < pairs.length; i++)
{
    if (curChar > 'Z')
    {
        throw new IndexOutOfBoundsException("Too many code points");
    }

    // Parse the pair as an integer
    int hex = Integer.parseInt(pairs[i], 16);

    // Add character to result set
    if (!codeMap.containsKey(hex))
    {
        codeMap.put(hex, curChar);
    }
    else curChar-=1;
    result[i] = codeMap.get(hex);

    // Increment character
    curChar++;
}
String viesti2 = new String(result);