将多行数据作为单个项读取

Question

我有一组来自这样一个文件的数据

"johnnyboy"=splice(23):15,00,30,00,31,00,32,02,39,00,62,00,a3,00,33,00,2d,0f,39,00,\
      00,5c,00,6d,00,65,00,64,00,69,00,61,00,5c,00,57,00,69,00,6e,00,64,00,6f,00,\
      77,00,73,00,20,00,41,00,61,00,63,00,6b,00,65,aa,72,00,6f,00,75,00,6e,dd,64,\
      00,2e,00,77,00,61,00,76,00,ff,00

"johnnyboy"="gotwastedatthehouse"

"johnnyboy"=splice(23):15,00,30,00,31,00,32,02,39,00,62,00,a3,00,33,00,2d,0f,39,00,\
      00,5c,00,6d,00,65,00,64,00,69,00,61,00,5c,00,57,00,69,00,6e,00,64,00,6f,00,\
      77,00,73,00,20,00,41,00,61,00,63,00,6b,00,65,aa,72,00,6f,00,75,00,6e,dd,64,\
      00,2e,00,77,00,61,00,76,00,ff,00


[mattplayhouse\wherecanwego\tothepoolhall]

如何阅读/引用“johnnyboy”=splice（23）作为单行的文本：

"johnnyboy"=splice(23):15,00,30,00,31,00,32,02,39,00,62,00,a3,00,33,00,2d,0f,39,00,00,5c,00,6d,00,65,00,64,00,69,00,61,00,5c,00,57,00,69,00,6e,00,64,00,6f,00,77,00,73,00,20,00,41,00,61,00,63,00,6b,00,65,aa,72,00,6f,00,75,00,6e,dd,64,00,2e,00,77,00,61,00,76,00,ff,00

我目前正在基于splice（23）匹配正则表达式：搜索如下：

re_johnny = re.compile('splice')
with open("file.txt", 'r') as file:
    read = file.readlines()
    for line in read:
        if re_johnny.match(line):
            print(line)

我想我需要取和删除反斜线和空间来合并这些线，但是我不熟悉如何去做，而不是获取空白线或不象我的正则表达式的新行。在尝试第一次解决方案时，我的最后一行被不适当地拉了出来。任何帮助都会很好。你知道吗

Answer 1

输入文件：fin

"johnnyboy"=splice(23):15,00,30,00,31,00,32,02,39,00,62,00,a3,00,33,00,2d,0f,39,00,\
      00,5c,00,6d,00,65,00,64,00,69,00,61,00,5c,00,57,00,69,00,6e,00,64,00,6f,00,\
      77,00,73,00,20,00,41,00,61,00,63,00,6b,00,65,aa,72,00,6f,00,75,00,6e,dd,64,\
      00,2e,00,77,00,61,00,76,00,ff,00

"johnnyboy"="gotwastedatthehouse"

"johnnyboy"=splice(23):15,00,30,00,31,00,32,02,39,00,62,00,a3,00,33,00,2d,0f,39,00,\
      00,5c,00,6d,00,65,00,64,00,69,00,61,00,5c,00,57,00,69,00,6e,00,64,00,6f,00,\
      77,00,73,00,20,00,41,00,61,00,63,00,6b,00,65,aa,72,00,6f,00,75,00,6e,dd,64,\
      00,2e,00,77,00,61,00,76,00,ff,00


[mattplayhouse\wherecanwego\tothepoolhall]

除了提格霍克的建议之外，你还可以尝试以下方法：

代码：

import re

with open('fin', 'r') as f:
    for l in [''.join([b.strip('\\') for b in a.split()]) for a in f.read().split('\n\n')]:
        if 'splice' in l:
            print(l)

输出：

"johnnyboy"=splice(23):15,00,30,00,31,00,32,02,39,00,62,00,a3,00,33,00,2d,0f,39,00,00,5c,00,6d,00,65,00,64,00,69,00,61,00,5c,00,57,00,69,00,6e,00,64,00,6f,00,77,00,73,00,20,00,41,00,61,00,63,00,6b,00,65,aa,72,00,6f,00,75,00,6e,dd,64,00,2e,00,77,00,61,00,76,00,ff,00
"johnnyboy"=splice(23):15,00,30,00,31,00,32,02,39,00,62,00,a3,00,33,00,2d,0f,39,00,00,5c,00,6d,00,65,00,64,00,69,00,61,00,5c,00,57,00,69,00,6e,00,64,00,6f,00,77,00,73,00,20,00,41,00,61,00,63,00,6b,00,65,aa,72,00,6f,00,75,00,6e,dd,64,00,2e,00,77,00,61,00,76,00,ff,00

Answer 2

使用regex，您的问题成倍增加。相反，保持简单：

• 如果一行以"开头，它就以一条记录开头。你知道吗
• 否则，将其附加到上一条记录。你知道吗

在Python中，只需几行就可以实现对这样一个方案的解析。你不需要正则表达式。你知道吗