为什么我的python字数计算程序不起作用?

2024-03-29 15:12:34 发布

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我正在学习python课程,其中一个问题要求我编写一个计算单词的程序,如下所示:

Enter line: which witch
Enter line: is which
Enter line: 
is 1
which 2
witch 1

到目前为止,我掌握的代码是:

occurences = {}

line = input('Enter line: ')
while line:
  m = line.split()
  for i in m:
    if i in occurences:
      occurences[i] += 1
    else:
      occurences[i] = 1
    line = input('Enter line: ')


for word in sorted(occurences):
  print(word, occurences[word])

但是当我运行这个代码时,它要么告诉我每个单词只出现过一次,要么告诉我其他一些奇怪的输出。谢谢你的帮助!你知道吗

下面是一个不起作用的例子:

Enter line: test test test
Enter line: one two test
Enter line: one
Enter line: 
test 3

这是我得到的输出,而预期的输出是:

test 4
two 1
one 2

Tags: 代码intestwhichforinputisline
2条回答

当我运行代码时,我没有得到任何输出,这是因为在“While”循环的末尾有一个无限循环,它要求用户输入另一行,从而导致无限循环。你知道吗

在我稍微修改你的代码之前你在做什么

occurences = {}
line = input('Enter line: ')

while line:
    m = line.split()
    for i in m:
        if i in occurences:
            occurences[i] += 1
        else:
            occurences[i] = 1
    break ## Once the word has been put into occurences it breaks
          ##    so that the next loop can run  


for word in sorted(occurences):
    print(word, occurences[word])

如果您希望它一直持续到用户退出程序,则可以执行以下操作:

while True:
    occurences = {}
    line = input('Enter line: ')

    while line:
        m = line.split()
        for i in m:
            if i in occurences:
                occurences[i] += 1
            else:
                occurences[i] = 1
        break

    for word in sorted(occurences):
        print(word, occurences[word])

for循环中的输入导致了问题,请尝试以下操作:

occurences = {}

line = input('Enter line: ')
while line:
  m = line.split()
  print( m)
  for i in m:

    if i in occurences:
      occurences[i] += 1
    else:
      occurences[i] = 1

    print(occurences)
  line = input('Enter line: ')


for word in sorted(occurences):
  print(word, occurences[word])

通过重置for循环中的输入,您将在计算第一个单词后请求新的输入,并忽略字符串中的后续单词。你知道吗

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