<p>我认为您需要<a href="http://pandas.pydata.org/pandas-docs/stable/generated/pandas.to_datetime.html" rel="nofollow noreferrer">^{<cd1>}</a>,但首先要在<a href="http://pandas.pydata.org/pandas-docs/stable/text.html#indexing-with-str" rel="nofollow noreferrer">indexing with str</a>和<a href="http://pandas.pydata.org/pandas-docs/stable/generated/pandas.Series.radd.html" rel="nofollow noreferrer">^{<cd2>}</a>年中删除前4个和最后4个字符:</p>
<pre><code>df['new'] = pd.to_datetime(df['from'].str[4:-4].radd('2017-'), format='%Y-%d. %b, %H:%M')
print (df)
from new
0 Di, 15. Aug, 21:52 Uhr 2017-08-15 21:52:00
1 Di, 15. Aug, 22:46 Uhr 2017-08-15 22:46:00
2 Di, 15. Aug, 22:46 Uhr 2017-08-15 22:46:00
3 Di, 15. Aug, 21:52 Uhr 2017-08-15 21:52:00
4 Di, 15. Aug, 22:46 Uhr 2017-08-15 22:46:00
5 Di, 15. Aug, 21:52 Uhr 2017-08-15 21:52:00
6 Di, 15. Aug, 22:46 Uhr 2017-08-15 22:46:00
7 Di, 15. Aug, 21:52 Uhr 2017-08-15 21:52:00
8 Di, 15. Aug, 22:46 Uhr 2017-08-15 22:46:00
</code></pre>
<p>最后一个要与今天的日期比较,请使用<a href="http://pandas.pydata.org/pandas-docs/stable/indexing.html#boolean-indexing" rel="nofollow noreferrer">^{<cd4>}</a>和<a href="http://pandas.pydata.org/pandas-docs/stable/generated/pandas.Series.dt.date.html" rel="nofollow noreferrer">^{<cd5>}</a>将pandas日期时间转换为python日期:</p>
<pre><code>today_date = pd.datetime.today().date()
df1 = df[df['new'].dt.date == today_date]
</code></pre>