绘制ROC cu时出现键错误

Question

我试图绘制一个多标签分类问题的ROC曲线。 在给目标列添加标签之前，它看起来像：

TargetGrouped
I5
I2
R0
I3

这是用于绘制ROC的代码的一部分：

    def computeROC(self, n_classes, y_test, y_score):
        # Compute ROC curve and ROC area for each class
        fpr = dict()
        tpr = dict()
        roc_auc = dict()

        # Compute micro-average ROC curve and ROC area
        fpr["micro"], tpr["micro"], _ = roc_curve(y_test.ravel(), y_score.ravel())
        roc_auc["micro"] = auc(fpr["micro"], tpr["micro"])

        # Plot ROC curve
        plt.figure()
        plt.plot(fpr["micro"], tpr["micro"],
                 label='micro-average ROC curve (area = {0:0.2f})'
                       ''.format(roc_auc["micro"]))
        for i in range(n_classes):
            plt.plot(fpr[i], tpr[i], label='ROC curve of class {0} (area = {1:0.2f})'
                                           ''.format(i, roc_auc[i]))

        plt.plot([0, 1], [0, 1], 'k--')
        plt.xlim([0.0, 1.0])
        plt.ylim([0.0, 1.05])
        plt.xlabel('False Positive Rate')
        plt.ylabel('True Positive Rate')
        plt.title('Some extension of Receiver operating characteristic to multi-class')
        plt.legend(loc="lower right")
        plt.show()

    lb = preprocessing.LabelBinarizer()
    infoDF = infoDF.join(pd.DataFrame(lb.fit_transform(infoDF["TargetGrouped"]), columns = lb.classes_, index = infoDF.index))

#Extracted features and split infoDF dataframe => got X_train, X_test, y_train, y_test

    rfc = RandomForestClassifier()
    rfc.fit(X_train, y_train)
    y_pred = rfc.predict(X_test)

    classes = y_train.shape[1]
    computeROC(classes, y_test, y_pred)

运行时，出现以下错误：

Traceback (most recent call last):

  File "<ipython-input-50-15a83ece5e44>", line 3, in <module>
    evaluation.computeROC(classes, y_test, y_pred)

  File "<ipython-input-49-526a19a07850>", line 18, in computeROC
    plt.plot(fpr[i], tpr[i], label='ROC curve of class {0} (area = {1:0.2f})'

KeyError: 0

我知道plt.plot()中的类的格式可能有问题，但我不知道如何解决它。你知道吗

更新

这是computeROC()中缺少的代码：

        for i in range(n_classes):
            fpr[i], tpr[i], _ = roc_curve(y_test[:, i], y_score[:, i])
            roc_auc[i] = auc(fpr[i], tpr[i])

Answer 1

问题实际上是这样的：

for i in range(n_classes):
            plt.plot(fpr[i], tpr[i], label='ROC curve of class {0} (area = {1:0.2f})'
                                           ''.format(i, roc_auc[i]))

fpr和tpr是字典，唯一初始化的键是'micro'。这个for循环将0和n_classes-1之间的整数值分配给i，但您从未定义过fpr[0]和tpr[0]是什么（我怀疑您认为它们是列表，但这只是猜测）。你知道吗