擅长:python、mysql、java
<p><a href="https://labix.org/python-dateutil#head-c0e81a473b647dfa787dc11e8c69557ec2c3ecd2" rel="noreferrer">^{<cd1>}</a>返回<a href="https://docs.python.org/3.4/library/datetime.html#datetime-objects" rel="noreferrer">^{<cd2>}</a>个对象,您可以相互减去这些对象,得到一个<a href="https://docs.python.org/3.4/library/datetime.html#timedelta-objects" rel="noreferrer">^{<cd3>}</a>对象,这是两次之间的差异。</p>
<p>然后可以使用<a href="https://docs.python.org/3.4/library/datetime.html#datetime.timedelta.total_seconds" rel="noreferrer">^{<cd4>}</a>方法来获取秒数。</p>
<pre><code>diff = date2 - date1
print(diff.total_seconds())
</code></pre>
<p>请注意,如果<code>date1</code>在未来比<code>date2</code>更远,那么<code>total_seconds</code>方法将返回一个负数。</p>