Python中的模式替换

Question

寻找一些替代方法来清理包含括号之间信息的表格文件。 这将是在管道中包含的第一步，我需要删除括号内的每个值（包括括号）。你知道吗

我所拥有的

> Otu00467  Bacteria(100);Gracilibacteria(99);unclassified(99);unclassified(99);unclassified(99);unclassified(99);
> Otu00469  Bacteria(100);Proteobacteria(96);unclassified(96);unclassified(96);unclassified(96);unclassified(96);
> Otu00470  Bacteria(100);Proteobacteria(100);Alphaproteobacteria(100);Rhodospirillales(100);Rhodospirillaceae(100);Azospirillum(54);

我想要的是：

 Otu00467   Bacteria;Gracilibacteria;unclassified;unclassified;unclassified;unclassified;
 Otu00469   Bacteria;Proteobacteria;unclassified;unclassified;unclassified;unclassified;
 Otu00470   Bacteria;Proteobacteria;Alphaproteobacteria;Rhodospirillales;Rhodospirillaceae;Azospirillum;

我的第一种方法是用“；”，“（”，“）”分隔第二列，然后进一步连接所有内容。不错，但太难看了。你知道吗

谢谢你。你知道吗

Answer 1

我想试试regexp。类似于：

pattern = re.compile('(\w+)\(\d+\);')
';'.join(re.findall(pattern, string))

对于每个字符串

Answer 2

这个正则表达式去掉了带圆括号的数字组，也去掉了任何'>'字符，因为看起来您也希望消除它们。你知道吗

import re

data = '''\
> Otu00467  Bacteria(100);Gracilibacteria(99);unclassified(99);>unclassified(99);unclassified(99);unclassified(99);
> Otu00469  Bacteria(100);Proteobacteria(96);unclassified(96);unclassified(96);unclassified(96);unclassified(96);
> Otu00470  Bacteria(100);Proteobacteria(100);Alphaproteobacteria(100);Rhodospirillales(100);Rhodospirillaceae(100);Azospirillum(54);
'''

data = re.sub(r'>|\(\d+\)', '', data)
print(data)

输出

 Otu00467  Bacteria;Gracilibacteria;unclassified;unclassified;unclassified;unclassified;
 Otu00469  Bacteria;Proteobacteria;unclassified;unclassified;unclassified;unclassified;
 Otu00470  Bacteria;Proteobacteria;Alphaproteobacteria;Rhodospirillales;Rhodospirillaceae;Azospirillum;

这段代码适用于python2&3。你知道吗

Answer 3

import re
new_string = re.sub(r'\(.*?\)', '', your_string)