urlopen错误[errno 111]连接被拒绝

Question

我正在用一本书“headfirst python”做python练习 使用python和sl4a制作android应用程序 我的代码是

import android
import json
import time

from urllib import urlencode
from urllib2 import urlopen

hello_msg     = "Welcome to Coach Kelly's Timing App"
list_title    = 'Here is your list of athletes:'
quit_msg      = "Quitting Coach Kelly's App."
web_server    = 'http://127.0.0.1:8080'
get_names_cgi = '/cgi-bin/generate_name.py'

def send_to_server(url, post_data=None):
    if post_data:
        page = urlopen(url, urlencode(post_data))
    else:
        page = urlopen(url)
    return(page.read().decode("utf8"))

app = android.Android()

def status_update(msg, how_long=2):
    app.makeToast(msg)
    time.sleep(how_long)

status_update(hello_msg)

athlete_names = sorted(json.loads(send_to_server(web_server + get_names_cgi)))
app.dialogCreateAlert(list_title)
app.dialogSetSingleChoiceItems(athlete_names)
app.dialogSetPositiveButtonText('Select')
app.dialogSetNegativeButtonText('Quit')
app.dialogShow()
resp = app.dialogGetResponse().result

status_update(quit_msg) 

这是我的代码，结果是

怎么了？？？ 我想不出问题在哪里。。。

Answer 1

使用10.0.2.2:8080

因为如果您在计算机127.0.0.1:（端口）中同时运行服务器和仿真器，本地IP将引用仿真器，那么您需要服务器的另一个本地IP，它将自动成为10.0.2.2

希望我把它弄清楚，很高兴我帮了忙