我有两个不同大小的数据帧。你知道吗
df1
有地址,没有zipcodes。
df2
有地址和zipcodes。你知道吗
我正在尝试使用np.where
匹配从df1
到df2
的地址,如果存在匹配,则将相应的zipcode带到df1
。你知道吗
不过,我刚刚意识到,这不适用于不同大小的数据帧。你知道吗
第一个没有zipcodes的数据帧:
df1 = pd.DataFrame({'address1':['1 o\'toole st','2 main st','3 high street','5 foo street','10 foo street'],
'address2':['town1',np.nan,np.nan,'Bartown',np.nan],
'address3':[np.nan,'village','city','county2','county3']})
df1['zipcode']=''
print(df1)
address1 address2 address3 zipcode
0 1 o'toole st town1 NaN
1 2 main st NaN village
2 3 high street NaN city
3 5 foo street Bartown county2
4 10 foo street NaN county3
要从中获取zipcodes的第二个数据帧:
df2 = pd.DataFrame({'address1':['1 o\'toole st','2 main st','7 mill street','5 foo street','10 foo street','asda'],
'address2':['town1','village','city','Bartown','county3','efsefs'],
'address3':[np.nan,np.nan,np.nan,'county2','USA','asdasd'],
'zipcode': ['er45','qw23','rt67','yu89','yu83','aedsa']})
print(df2)
address1 address2 address3 zipcode
0 1 o'toole st town1 NaN er45
1 2 main st village NaN qw23
2 7 mill street city NaN rt67
3 5 foo street Bartown county2 yu89
4 10 foo street county3 USA yu83
5 asda efsefs asdasd aedsa
使用np.where
填充df1['zipcode']
列。如果两个地址都匹配,则返回df2['zipcode']
否则'no_match'
:
df1['zipcode'] = np.where(df1['address1'].isin(df2['address1']), df2['zipcode'], 'no_match')
ValueError Traceback (most recent call last)
<ipython-input-176-499624d43d5c> in <module>
----> 1 df1['zipcode'] = np.where(df1['address1'].isin(df2['address1']), df2['zipcode'], 'no_match')
2 df1
ValueError: operands could not be broadcast together with shapes (5,) (6,) ()
有没有可能这样做np.哪里'和不同大小的数据帧?或者有没有更好的方法来搜索匹配项并跨越zipcode?你知道吗
对} ,对于no match get missing value,最后添加
fillna
创建的新列key
使用^{fillna('no_match')
:可以使用合并:
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