21点python脚本，重新启动gam时出现流错误

Question

我是一个Python新手，但我试过写21点脚本。在调试并纠正了所有明显的错误之后，我遇到了一个我无法理解的奇怪事件。你知道吗

当total是>；21时，它似乎跳过了while (total < 21) and (stand != True):代码块，即使在游戏循环的开始我将所有相关变量归零。你知道吗

我花了太多的时间试图弄清楚这一点，我不能不认为这有一个明显的解决办法。你知道吗

我不明白为什么while (total < 21) and (stand != True):似乎被跳过，即使它应该是一个真正的声明在每一场比赛的开始。你知道吗

下面是完整的代码。你可以自己测试一下，看看我的意思。你知道吗

import pygame
import random

print("Welcome to PyBlackjack V1.0")
done =  False

while not done:

    # --- Reset our Hands ---

    dealerhand = 0
    split = False
    stand = False
    total = 0

    # --- Dealing the Player's hand. ---

    print("Dealer is dealing hand.")
    firstcard = random.randrange(1, 15)
    print("First card:",str(firstcard),)
    secondcard = random.randrange(1, 15)
    print("Second card:",str(secondcard),)

    total = (firstcard + secondcard)

    print("Hand:",str(total),)

        # --- Bust Check ---

    if total > 21:
        print("Bust! Game Over.")
        newgame = input("Play again? Y/N: ")
        if str(newgame) == "n":
            done = True
            break
        else:
            print("Starting new game! Good Luck!")

    dealerfirstcard = random.randrange(1, 15)
    dealerholecard = random.randrange(1, 15)

    dealerhand = (dealerfirstcard + dealerholecard)

    print("Dealer's Hand:",str(dealerfirstcard))

    # --- Player decides what to do ---

    while (total < 21) and (stand != True):

        if split != True:
            print("Hand:",str(total))
        elif split == True:
            print("Left hand:",str(lefthand),"| Right hand:",str(righthand))

        playerchoice = input("Hit (1), Double Down(2), Split(3), Stand(4)?")

        if int(playerchoice) == 1:
            total += random.randrange(1, 15)
        elif int(playerchoice) == 2:
            #Reserved
            break
        elif int(playerchoice) == 3:
            if ((firstcard + secondcard) / 2) == firstcard and split != True:
                lefthand = (firstcard + random.randrange(1, 15))
                righthand = (secondcard + random.randrange(1, 15))
                split = True
            else:
                print("You cannot split this hand!")
        elif int(playerchoice) == 4:
            print("You stand.")
            stand = True
        else:
            print("Invalid Choice!")

    print("Hand:",total,)

    if total > 21:
        print("Bust! Game Over.")

    newgame = input("Play again? Y/N: ")
    if str(newgame) == "n":
        done = True
        break
    else:
        print("Starting new game! Good Luck!")

    print("Dealer reveals hole card...")
    print("Dealer Hand:",str(dealerhand),)

    # --- Dealer hits until >= 17 ---

    while dealerhand < 17:
        print("Dealer hits...")
        dealerhand = (dealerhand + random.randrange(1, 15))
        print("Dealer hand:",dealerhand,)

    # --- Deciding who wins ---

    if dealerhand > 21:
        print("Dealer busts! You win!")
    elif dealerhand >= 17:
        print("Your hand:",total,"| Dealer hand:",dealerhand,)
        if split != True:
            if dealerhand >= total:
                print("You lose!")
            elif dealerhand < total:
                print("You win!")
        elif split == True:
            if lefthand > dealerhand:
                print("Left hand wins!")
            elif lefthand < dealerhand:
                print("Left hand loses!")
            else:
                print("An error occured. Ending program.")
                done = True
                break

            if righthand > dealerhand:
                print("Right hand wins!")
            elif righthand < dealerhand:
                print("Right hand loses!")
            else:
                print("An error occured. Ending program.")
                done = True
                break

    # --- To loop or not to loop ---

    newgame = input("Play again? Y/N: ")
    if str(newgame) == "n":
        done = True
        break
    else:
        print("Starting new game! Good Luck!")

Answer 1

看起来您正在{未完成时：}内玩游戏 只有当玩家键入“n”时，它才会中断 但是启动新游戏的函数在代码中比变量赋值要晚，我相信，变量赋值永远不会重新启动。 另外，如果你把它分解成更小的函数或方法，它也会帮助你编写代码。你知道吗

Answer 2

下面是（某种）工作代码。它仍然实现了21点的一个奇数变体（等级从1到15，没有1或11的王牌，击球后可以分开）。一般来说，分裂在这里处理得不好。。。我想你可以分开，然后仍然打/等等。？但是击打不会更新任何一只分开的手，再次分开也不会起任何作用。我把那些逻辑错误留给你去解决。你知道吗

我认为你所描述的问题最好用@Martin的回答来解释。最后我用一个else来简化这个逻辑，以处理非半身像的情况。顺便说一句，如果您真正想要的只是break，则不需要使用stand或done这样的标志来退出循环。你知道吗

我还清理了一些杂物。。。删除了一些对str不必要的转换，清理了检测玩家半身像、检测和打印推送等逻辑。请参阅下面的完整代码并注意区别。你知道吗

import random

print("Welcome to PyBlackjack V1.0")

while True:
    #  - Reset our Hands  -
    dealerhand = 0
    split = False
    total = 0

    #  - Dealing the Player's hand.  -
    print("Dealer is dealing hand.")
    firstcard = random.randrange(1, 15)
    print("First card:", firstcard)
    secondcard = random.randrange(1, 15)
    print("Second card:", secondcard)

    total = firstcard + secondcard

    print("Hand:", total)

    dealerfirstcard = random.randrange(1, 15)
    dealerholecard = random.randrange(1, 15)

    dealerhand = dealerfirstcard + dealerholecard

    print("Dealer's hole card:", dealerfirstcard)

    #  - Player decides what to do  -
    while total < 21:
        if not split:
            print("Hand:", total)
        else:
            print("Left hand:", lefthand, "| Right hand:", righthand)

        playerchoice = int(input("Hit (1), Double Down(2), Split(3), Stand(4)? "))

        if playerchoice == 1:
            total += random.randrange(1, 15)
        elif playerchoice == 2:
            #Reserved
            break
        elif playerchoice == 3:
            # NOTE: This will allow splitting even after hitting
            if firstcard == secondcard and not split:
                lefthand = firstcard + random.randrange(1, 15)
                righthand = secondcard + random.randrange(1, 15)
                split = True
            else:
                print("You cannot split this hand!")
        elif playerchoice == 4:
            print("You stand.")
            break
        else:
            print("Invalid Choice!")

    print("Hand:", total)

    if total > 21:
        print("Bust! Game Over.")
    else:
        print("Dealer reveals hole card...")
        print("Dealer hand:", dealerhand)

        #  - Dealer hits until >= 17  -
        while dealerhand < 17:
            print("Dealer hits...")
            dealerhand += random.randrange(1, 15)
            print("Dealer hand:", dealerhand)

        #  - Deciding who wins  -
        if dealerhand > 21:
            print("Dealer busts! You win!")
        else:
            print("Your hand:", total, "| Dealer hand:", dealerhand)
            if not split:
                if dealerhand >= total:
                    print("You lose!")
                elif dealerhand < total:
                    print("You win!")
                else:
                    print("Push.")
            else:
                if lefthand > dealerhand:
                    print("Left hand wins!")
                elif lefthand < dealerhand:
                    print("Left hand loses!")
                else:
                    print("Push.")

                if righthand > dealerhand:
                    print("Right hand wins!")
                elif righthand < dealerhand:
                    print("Right hand loses!")
                else:
                    print("Push.")

    #  - To loop or not to loop  -
    newgame = input("Play again? Y/N: ")
    if str(newgame) == "n":
        break
    else:
        print("Starting new game! Good Luck!")

Answer 3

如果用户失败并选择开始一个新游戏，那么您的代码不会从while not done循环开始，而是继续向前。因此，当您到达while (total < 21) and (stand != True)行时，total仍然是导致用户崩溃的total。你知道吗