我已经将一个函数转换为使用线程(按照this answer)。它的行为与测试中预期的一样(也就是说,它向非线程版本返回相同的值)。但是,使用ctypes
从Python调用它会导致调用进程崩溃。你知道吗
一是工作职能:
#[no_mangle]
pub extern fn convert_vec(lon: Array, lat: Array) -> Array {
// snip
// orig is a Vec<(f32, f32)>
// convert is a conversion function
let result: Vec<(i32, i32)> = orig.iter()
.map(|elem| convert(elem.0, elem.1))
.collect();
// convert back to vector of unsigned integer Tuples
let nvec = result.iter()
.map(|ints| Tuple { a: ints.0 as u32, b: ints.1 as u32 })
.collect();
Array::from_vec(nvec)
}
现在是线程版本,它通过了测试(使用cargo test
),但从Python调用时崩溃:
#[no_mangle]
pub extern fn convert_vec_threaded(lon: Array, lat: Array) -> Array {
// snip
// orig is a Vec<(f32, f32)>
// convert is a conversion function
let mut guards: Vec<JoinHandle<Vec<(i32, i32)>>> = vec!();
// split into slices
for chunk in orig.chunks(orig.len() / NUMTHREADS as usize) {
let chunk = chunk.to_owned();
let g = thread::spawn(move || chunk
.into_iter()
.map(|elem| convert(elem.0, elem.1))
.collect());
guards.push(g);
}
let mut result: Vec<(i32, i32)> = Vec::with_capacity(orig.len());
for g in guards {
result.extend(g.join().unwrap().into_iter());
}
// convert back to vector of unsigned integer Tuples
let nvec = result.iter()
.map(|ints| Tuple { a: ints.0 as u32, b: ints.1 as u32 })
.collect();
Array::from_vec(nvec)
}
完整的可测试示例可用here
从错误消息来看,您似乎对某些输入使用了
0
的块大小。[T]::chunks(size)
将断言size != 0
。你知道吗如果我们想要
NUMTHREADS
块,我们可以这样分割它:相关问题 更多 >
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