java Android为按钮分配数组值

Question

我正在做一个类似于徽标测验的问答游戏，我正在尝试创建应用程序所使用的输入样式。它们有随机混合的字母，用户必须找到组成正确答案的字母。到目前为止，我有一个包含按钮和正确答案字母的数组列表，然后我在数组列表中循环，并将按钮文本分配给正确答案数组列表中的字母，但导致强制停止而没有错误。有人知道为什么吗

ArrayList<Character> answer = new ArrayList<Character>();
ArrayList<Button> buttons = new ArrayList<Button>();

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    Button btn1 = (Button) findViewById(R.id.button1);
    Button btn2 = (Button) findViewById(R.id.button2);
    Button btn3 = (Button) findViewById(R.id.button3);
    Button btn4 = (Button) findViewById(R.id.button4);
    Button btn5 = (Button) findViewById(R.id.button5);
    Button btn6 = (Button) findViewById(R.id.button6);
    Button btn7 = (Button) findViewById(R.id.button7);
    Button btn8 = (Button) findViewById(R.id.button8);
    Button btn9 = (Button) findViewById(R.id.button9);
    buttons.add(btn1);
    buttons.add(btn2);
    buttons.add(btn3);
    buttons.add(btn4);
    buttons.add(btn5);
    buttons.add(btn6);
    buttons.add(btn7);
    buttons.add(btn8);
    buttons.add(btn9);

    String testAnswer = "Answer";
    //convert to chars and add to arraylist for shuffling
    for(char a : testAnswer.toCharArray()){
        answer.add(a);
    }
    Collections.shuffle(answer);


    //loop over buttons and letters and assign each button with a letter
    for(char a : answer){
        for(Button bb : buttons){
            bb.setText(String.valueOf(a));
        }
    }

}

Answer 1

String[] Herifler={"q","ü","e","r","t","y","u","i","o","p","ö","ğ","a","s","d","F","G","H","J","K","L","ı","ə","Z","X","C","V","B","N","M","ç","ş"};

for(in i=0;i<30;i++) {
   buttons.get(i).setText(Herifler[i]);
}

Collections.shuffle(buttons);

Answer 2

我不明白为什么应用程序强制停止了你给出的代码（看起来不错），但我发现了另一个问题：

//loop over buttons and letters and assign each button with a letter
for(char a : answer){
    for(Button bb : buttons){
        bb.setText(String.valueOf(a));
    }
}

此代码不会为每个按钮分配不同的字母，而是为所有按钮分配相同的字母
而是这样做：

// omit unnecessary answer.shuffle() (`answer` will be shuffled anyway afterwards)

String allowed = "abcdefghijklmnopqrstuvwxy"; // add all allowed characters here

for (int i = 0; i < answer.size(); i++)
    buttons.get(i).setText("" + answer.get(i));

Random r = new Random();
for (int j = answer.size(); i < buttons.size(); j++)
    buttons.get(j).setText("" + allowed.charAt(r.nextInt(0, allowed.length())); // get a random character from `allowed`

Collection.shuffle(buttons); // shuffle buttons, so that they are in random order

如果您不希望字符出现多次，可以在将它们设置为按钮文本后将其从allowed中删除

Answer 3

你可以做以下几点：

Button btn;
for(int i = 0; i < answer.size(); i++){
   btn = buttons.get(Math.random() * (buttons.size()+1))
   if(btn.getText == null){
        btn.setText(String.valueOf(answer.get(i)));
   }
}

然后用随机字母填充剩下的部分：

char[] alphabet = "abcdefghijklmnopqrstuvwxyz".toCharArray();

// char[] alphabet = [a-z] May also work ;)

for(Button b: buttons){
    if(b.getText == null){
        b.setText(String.valueOf(answer.get(Math.random() * (alphabet.size()+1)));
    }
}

假设这是可行的，这应该在一个随机按钮中放入一个“答案”字母，然后用a-z中的其他字母填充其他按钮

p.S:这假设按钮文本默认为“null”，您可以/应该更改这一点