我想知道我的敌人是否在防御塔200像素以内,这样我就可以开始夺走敌人的生命。敌人正在移动,防务仍在继续。如果有人能给我建议怎么做这将是惊人的。如果我把我的代码了,它只会混淆每个人,因为我的代码是非常混乱,所以只要给我的建议,如何做到这一点,谢谢。尼克。我添加了我的代码,因为我知道我做错了什么,如果有人有时间通读它,告诉我我做错了什么,这可能是我非常感激的一切。你知道吗
import pygame
import math
from pygame.locals import *
def text():
font = pygame.font.SysFont("monospace", 14)
text = font.render("Start Round", True, black)
textpos = text.get_rect()
textpos.center = (790,675)
Background.blit(text, textpos)
def newRound():
pos = pygame.mouse.get_pos()
click = pygame.mouse.get_pressed()
if 730 < pos[0] < 850 and 650 < pos[1] < 800:
pygame.draw.rect(Background, (150,150,150), (730,650,120,50))
if click[0] == 1:
startGame()
else:
pygame.draw.rect(Background, (100,100,100), (730,650,120,50))
def startGame():
global startRound, endRound, intro
intro = 0
createRound()
intro = 1
startRound = True
endRound = False
def lifeText(lifes):
font = pygame.font.SysFont("monospace", 20)
text = font.render("Lives %s" % (lifes) , True, black)
textpos = text.get_rect()
textpos.center = (60,30)
Background.blit(text, textpos)
def life(self):
global hit, endRound, startRound, noEnemies, lifes
if noEnemies == 0 and lifes > 0:
startRound = False
endRound = True
if self.rect.x == 960:
hit = hit + 1
lifes = lifes - 1
if lifes == 0:
print("You have 0 lives Game Over")
pygame.quit()
if hit == 4:
startRound = False
endRound = True
hit = 0
noEnemies = noEnemies + 1
def createRound():
global enemies, noEnemies
enemies = []
x = -40
y = 210
for e in range(noEnemies):
x = x - 80
enemies.append(yellowEnemy(x, y, Background))
noEnemies = len(enemies)
def displayTower():
for tower in towers:
Background.blit(redtower, (tower))
class yellowEnemy(object):
image1 = pygame.image.load("enemySpriteFullHealth.jpg")
image2 = pygame.image.load("enemySpriteHalfHealth.jpg")
image3 = pygame.image.load("enemySpriteDead.jpg")
def __init__(self, x, y, Background):
self.Background = Background
self.Background_rect = Background.get_rect()
self.rect = self.image1.get_rect()
self.rect = self.image2.get_rect()
self.rect = self.image3.get_rect()
self.rect.x = x
self.rect.y = y
self.health = 20
self.dist_x = 2
self.dist_y = 0
def update(self):
self.rect.x += self.dist_x
self.rect.y += self.dist_y
def draw(self, Background):
timeDead = 0
if self.health > 9 and self.health < 21:
Background.blit(self.image1, self.rect)
elif self.health < 10 and self.health > 1:
Background.blit(self.image2, self.rect)
elif self.health < 1:
Background.blit(self.image3, self.rect)
self.dist_x = 0
life(self)
pygame.init()
width = 960
height = 720
black = (0,0,0)
lifes = 10
hit = 0
intro = 1
FPS = 200
noEnemies = 4
bx = 1000
by = 1000
towers = []
endRound = True
startRound = False
clicked = False
mx, my = pygame.mouse.get_pos()
clock = pygame.time.Clock()
test= False
mapImg = pygame.image.load("mapimage.jpg")
redtower = pygame.image.load("redTower.jpg")
Background = pygame.display.set_mode((width, height))
Background_rect = Background.get_rect()
while intro == 1:
mousePos = pygame.mouse.get_pos()
mousePressed = pygame.mouse.get_pressed()
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
if 530 < mousePos[0] < 590 and 650 < mousePos[1] < 710:
if mousePressed[0] == 1:
clicked = True
if clicked == True:
mx, my = pygame.mouse.get_pos()
pygame.display.update()
bx = 30
by = 30
if mousePressed[0] == 0:
clicked = False
tx = mx - bx
ty = my - by
towerCords = tx, ty
towers.append(towerCords)
if endRound == True:
Background.blit(mapImg, (0,0))
newRound()
text()
if startRound == True:
for enemy in enemies:
enemy.update()
Background.blit(mapImg, (0,0))
for enemy in enemies:
enemy.draw(Background)
Background.blit(redtower, (mx-bx, my-by))
if clicked == True:
pygame.draw.circle(Background, (220, 0, 0), (mx, my), 200, 4)
displayTower()
lifeText(lifes)
Background.blit(redtower, (530,650))
pygame.display.update()
clock.tick(FPS)
如果它们是精灵,您可以简单地执行以下操作:
逻辑是看敌人的中心距防御中心的距离是否为200像素(因此使用
math.abs()
,这是绝对值)。如果是,则用代码替换注释。为什么这样做? 检查here。你知道吗要查找两点之间的距离,可以使用以下代码:
这也要求您在程序开始时
import math
。你知道吗Pygame有pygame.Rect()来保持对象的位置和大小。你知道吗
塔
200x200
,左上角在点(0,0)
或者你可以把它移到
(0,0)
的中心检查其他
Rect()
是否完全在塔内或者如果它完全或部分地在塔中(它与塔一起冷却)
你可以用敌人列表进行事件测试
或者用所有的塔来对付一个敌人
相关问题 更多 >
编程相关推荐