获取所有早于x天的文件夹（os.walk），d

Question

如何简洁地表达“获取x天以上的所有文件夹”

我有一个方法getOldDirs（dirPath，older than days），它必须遍历一个给定的根文件夹，并返回一个比7天旧的文件夹列表。

我从另一个函数cleanOldFolders（）调用上面的函数。cleanOldFolders（）将删除类似于“rm-Rf”的文件夹

我拥有的代码，如何简洁地修改循环：

"""
Clean oldFolders
"""
def cleanOldFolders(self):
    pathString = self.folderRoot + '/' + self.configMode + '/' + self.appId
    oldDirList = self.getOldDirs(pathString, 7);
    # Notify user that the following folders are deleted

    # remove all old dirs perhaps using shutil.removetree for each folder oldDirList, rm -Rf

    return

得到老德尔斯：

"""
get all subfolders under dirPath older than olderThanDays
"""
def getOldDirs(self,dirPath, olderThanDays):
    # What is the concise way of expressing Get me list of all dir/subdirs from "dirPath" that are older than "olderThanDays"
    # I know I have to use os.walk,
    # I want a concise loop like this - but should recurse using os.walk
    a = [os.path.join(dirPath, myfile) for myfile in os.listdir(dirPath)
            if (os.path.isdir(os.path.join(dirPath, myfile)) and
                (self.isOlder(os.path.join(dirPath, myfile), olderThanDays))
        )]

#  for root, dirs, files in os.walk(dirPath):
#      for name in dirs:
#          print os.path.join(root, name)

    return a

Answer 1

它使用os.walk并为您提供7天以上的文件列表

import os
from datetime import date

old_dirs = []
today = date.today()

for root, dirs, files in os.walk(start_path):
    for name in dirs:
        filedate = date.fromtimestamp(os.path.getmtime(os.path.join(root, name)))
        if (today - filedate).days > 7:                                            
            old_dirs.append(name)

Answer 2

这应该是一个起点。

import os
from time import time as _time

SEVEN_DAYS = 60*60*24*7

def get_old_dirs(dir_path, older_than=SEVEN_DAYS):
    time_now = _time()
    for path, folders, files in os.walk(dir_path):
        for folder in folders:
            folder_path = os.path.join(path, folder)
            if (time_now - os.path.getmtime(folder_path)) > older_than:
                yield folder_path

list_of_folders = list(get_old_dirs("/some/path"))

另外，如果您不想进入早于older_than天的文件夹（因为您要删除它们），您可以修剪搜索树，从folders列表中删除文件夹名

def get_old_dirs(dir_path, older_than=SEVEN_DAYS):
    time_now = _time()
    for path, folders, files in os.walk(dir_path):
        for folder in folders[:]:
            folder_path = os.path.join(path, folder)
            if (time_now - os.path.getmtime(folder_path)) > older_than:
                yield folder_path
                folders.remove(folder)

Answer 3

关于os.walk()的一个好处是它为您执行递归。为了在应用程序中使用它，必须将可选的关键字参数指定为False，因为它的默认值是True，并且os.rmdir()不会删除非空目录。

这意味着在删除子目录之前，您的代码需要删除它遇到的每个子目录中的所有文件和子目录。为了方便这样做，目录列表getOldDirs()返回应该按照需要删除子目录的顺序。

还需要注意的是，在下面的代码中，目录的时间是以小数而不是整天计算的，这意味着秒数是有意义的，也就是说，6天23小时59秒的时间不会被放到要删除的列表中，即使它离足够大的时间只有2秒。

import os
import time

def getOldDirs(self, dirPath, olderThanDays):
    """
    return a list of all subfolders under dirPath older than olderThanDays
    """
    olderThanDays *= 86400 # convert days to seconds
    present = time.time()
    for root, dirs, files in os.walk(dirPath, topdown=False):
        for name in dirs:
            subDirPath = os.path.join(root, name)
            if (present - os.path.getmtime(subDirPath)) > olderThanDays:
                yield subDirPath