2024-03-28 14:15:38 发布
网友
我最好的尝试失败了:
for s in self.services: for m in s.messages: yield m
itertools.chain.from_iterable(s.messages for s in self.services)
(m for s in self.services for m in s.messages)
。。。似乎有悖常理。你知道吗
itertools.chain.from_iterable(s.messages for s in self.services)
(m for s in self.services for m in s.messages)
。。。似乎有悖常理。你知道吗
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