如何在python中多次使用if循环？

Question

def hit():
    global hitsum
    hitsum = 0
    v=random.choice(cards)
    c=random.choice(suits)
    if v=="Ace":
        hitsum=hitsum+1
        print "You were dealt","a",v,"of",c
    elif v=="Jack":
        hitsum=hitsum+11
        print "You were dealt","a",v,"of",c
    elif v=="Queen":
        hitsum=hitsum+12
        print "You were dealt","a",v,"of",c
    elif v=="King":
        hitsum=hitsum+13
        print "You were dealt","a",v,"of",c
    else:
        hitsum=hitsum+v
        print "You were dealt","a",v,"of",c

computer()

choice=raw_input("Would you like to hit or stay? ")
if choice=="hit":
    hit()
    totalsum = hitsum + usersum
    print "Your total is", totalsum

elif choice=="stay":
    totalsum=usersum

else:
    print "Invalid request"

这段代码是我21点游戏的摘录。我做了一个用户定义的函数，每当有人要求点击时随机生成一张卡。然而，这只适用于一种选择。如果我选择命中一次，我就不能再选择了。我该如何纠正？你知道吗

Answer 1

choice=raw_input("Would you like to hit or stay? ")
while choice=="hit":
    hit()
    totalsum = hitsum + usersum
    print "Your total is", totalsum
    choice=raw_input("Would you like to hit or stay? ")

我强烈建议更改hit和hitsum的处理方式。与其让它全球化，为什么不退货呢？所以在hit的结尾，你会

return hitsum

所以在电话里你可以

totalsum = usersum + hit()

我也看到了其他一些问题。下一次通过choice==hit循环时，usersum将恢复到以前的状态。我不认为那是你想要的。当然你想把usersum增加hitsum。在这种情况下，将totalsum = ...替换为

usersum += hit()

最后，在hit函数中，为什么要在开头定义hitsum=0？你知道吗