在Python中将.txt文件转换为图像

Question

我有一些代码可以将图像转换为ascii艺术图像。 目前它输出为一个.txt文件，但该文件可以有几十万个字符。如何将文件转换为.png文件等图像？

目前，它基于像素密度构建一个字符向量，然后将该向量写入一个.txt图像。

Answer 1

如果我理解正确，你需要一个图像，看起来像是有人采取了一个ascii艺术的屏幕截图，因为它将在一个巨大的无限文本编辑器。

我做了一些类似的事情，用枕头编程生成文本。这是一个由我的this代码修改的示例。希望这段代码能帮助您和其他人避免我为了弄清楚如何使事情看起来合理而不得不做的手脚。

下面是由下面的代码生成的一个示例结果。

代码是对链接库的直接修改，以便使用文本文件而不是字符串。

import PIL
import PIL.Image
import PIL.ImageFont
import PIL.ImageOps
import PIL.ImageDraw

PIXEL_ON = 0  # PIL color to use for "on"
PIXEL_OFF = 255  # PIL color to use for "off"


def main():
    image = text_image('content.txt')
    image.show()
    image.save('content.png')


def text_image(text_path, font_path=None):
    """Convert text file to a grayscale image with black characters on a white background.

    arguments:
    text_path - the content of this file will be converted to an image
    font_path - path to a font file (for example impact.ttf)
    """
    grayscale = 'L'
    # parse the file into lines
    with open(text_path) as text_file:  # can throw FileNotFoundError
        lines = tuple(l.rstrip() for l in text_file.readlines())

    # choose a font (you can see more detail in my library on github)
    large_font = 20  # get better resolution with larger size
    font_path = font_path or 'cour.ttf'  # Courier New. works in windows. linux may need more explicit path
    try:
        font = PIL.ImageFont.truetype(font_path, size=large_font)
    except IOError:
        font = PIL.ImageFont.load_default()
        print('Could not use chosen font. Using default.')

    # make the background image based on the combination of font and lines
    pt2px = lambda pt: int(round(pt * 96.0 / 72))  # convert points to pixels
    max_width_line = max(lines, key=lambda s: font.getsize(s)[0])
    # max height is adjusted down because it's too large visually for spacing
    test_string = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'
    max_height = pt2px(font.getsize(test_string)[1])
    max_width = pt2px(font.getsize(max_width_line)[0])
    height = max_height * len(lines)  # perfect or a little oversized
    width = int(round(max_width + 40))  # a little oversized
    image = PIL.Image.new(grayscale, (width, height), color=PIXEL_OFF)
    draw = PIL.ImageDraw.Draw(image)

    # draw each line of text
    vertical_position = 5
    horizontal_position = 5
    line_spacing = int(round(max_height * 0.8))  # reduced spacing seems better
    for line in lines:
        draw.text((horizontal_position, vertical_position),
                  line, fill=PIXEL_ON, font=font)
        vertical_position += line_spacing
    # crop the text
    c_box = PIL.ImageOps.invert(image).getbbox()
    image = image.crop(c_box)
    return image


if __name__ == '__main__':
    main()

顺便说一句，所有的代码可能不应该被塞进一个函数中，但我认为这会使它更简单，例如代码。

Answer 2

看看Pillow（文档here）

从上述链接的文档中：

Here’s a simple example:

import ImageFont, ImageDraw

draw = ImageDraw.Draw(image)

# use a bitmap font
font = ImageFont.load("arial.pil")

draw.text((10, 10), "hello", font=font)

# use a truetype font
font = ImageFont.truetype("arial.ttf", 15)

draw.text((10, 25), "world", font=font)