Python文本中的重复单词Fi

Question

我有一个txt文件

文本文件如下所示：

还是没用。在

['None']['Vega~']['Vega~']['Vega~']['8^)->-<']['violence']['puker']['Zanaz']['Funk']['8^)->-<']['8^)->-<']['8^)->-<']['Vega~']['violence']['Zanaz']['Funk']['puker']['Vega~']['Vega~']['Vega~']['8^)->-<']['violence']['puker']['Zanaz']['None']['Lawn']['Lawn']['Lawn']['Leafy']['Judge69']['David']['lilwade']['Pity.']['artofwar']['Hazecloud']['Lawn']['Lawn']['Lawn']['Judge69']['Leafy']['David']['lilwade']['Hazecloud']['Lawn']['Lawn']['Lawn']['Leafy']['David']['Pity.']['lilwade']['artofwar']['Judge69']

我需要删除所有的重复，这样每个名字应该只显示一次，也必须保持他们的顺序。在

   fo = open('C:\Python26\myfile.txt','r')
   name_cache = fo.readlines()
   typea = name_cache[0]

   def unique_list(l):
      ulist = []
      [ulist.append(x) for x in l if x not in ulist]
      return ulist

   mast =' '.join(unique_list(typea.split()))
   print mast

Answer 1

s = "['None']['Vega~']['Vega~']['Vega~']['8^)->-<']['violence']['puker']['Zanaz']['Funk']['8^)->-<']['8^)->-<']['8^)->-<']['Vega~']['violence']['Zanaz']['Funk']['puker']['Vega~']['Vega~']['Vega~']['8^)->-<']['violence']['puker']['Zanaz']['None']['Lawn']['Lawn']['Lawn']['Leafy']['Judge69']['David']['lilwade']['Pity.']['artofwar']['Hazecloud']['Lawn']['Lawn']['Lawn']['Judge69']['Leafy']['David']['lilwade']['Hazecloud']['Lawn']['Lawn']['Lawn']['Leafy']['David']['Pity.']['lilwade']['artofwar']['Judge69']"
ss = s[1:-1]
l = []
for i in ss.split(']['):
    if i not in l:
        l.append(i)
r = ' '.join(l)

结果是：

^{pr2}$

Answer 2

您可以这样做：

import collections
def unique_list(l): return list(OrderedSet(l))

而且，typea只是一个没有空格的字符串。要拆分名称，请执行以下操作：

^{pr2}$

Answer 3

首先删除前导[和尾随]。然后split在][上。例如

>>> x="['None']['Vega~']['Vega~']"
>>> x.rstrip(']').lstrip('[').split('][') 
["'None'", "'Vega~'", "'Vega~'"]

然后打电话给你的unique_list。在

^{pr2}$

然后您可以轻松地将其格式化为您想要的任何格式（即字符串）。在

注意，rstrip和{}都是O（n）。所以最好是x[1:-1]。这假设您100%确定输入是给定形式（以[开头，以]结尾）

这与散列每个单词（添加到python集合中）具有相同的O（n）时间复杂性，但保持了原始顺序，并使用了您的（相当简洁的）unique_list函数。在