在两个文件中找到唯一的句子

Question

我有两个文件，我试图打印两个文件之间的独特句子。为此，我在python中使用difflib。在

text ='Physics is one of the oldest academic disciplines. Perhaps the oldest through its inclusion of astronomy. Over the last two millennia. Physics was a part of natural philosophy along with chemistry.'
text1 ='Physics is one of the oldest academic disciplines. Physics was a part of natural philosophy along with chemistry. Quantum chemistry is a branch of chemistry.'
import difflib

differ = difflib.Differ()
diff = differ.compare(text,text1)
print '\n'.join(diff)

它没有给我想要的输出。它给了我这样的感觉。在

^{pr2}$

我想要的输出只是两个文件之间唯一的句子。在

text = Perhaps the oldest through its inclusion of astronomy. Over the last two millennia.

text1 = Quantum chemistry is a branch of chemistry.

而且看起来差异。不同是逐行而不是逐句逐句。有什么建议吗。我怎么能做到呢？在

Answer 1

正如DZinoviev上面所述，您将字符串传递到一个需要列表的函数中。您不需要使用NLTK，相反，您可以通过在句点上拆分来将字符串转换为句子列表。在

import difflib

text1 ="""Physics is one of the oldest academic disciplines. Perhaps the oldest through its inclusion of astronomy. Over the last two millennia. Physics was a part of natural philosophy along with chemistry."""
text2 ="""Physics is one of the oldest academic disciplines. Physics was a part of natural philosophy along with chemistry. Quantum chemistry is a branch of chemistry."""

list1 = list(text1.split("."))
list2 = list(text2.split("."))

differ = difflib.Differ()
diff = differ.compare(list1,list2)
print "\n".join(diff)

Answer 2

首先，Differ（）.compare（）比较的是行，而不是句子。在

第二，它实际上比较序列，比如字符串列表。但是，传递的是两个字符串，而不是两个字符串列表。由于字符串也是一个（字符）序列，因此在您的示例中Differ（）.compare（）将比较各个字符。在

如果你想用句子比较文件，你必须准备两个句子列表。你可以用nltk.sent_标记化（文本）将字符串拆分成句子。在

diff = differ.compare(nltk.sent_tokenize(text),nltk.sent_tokenize(text1))
print('\n'.join(diff))
#  Physics is one of the oldest academic disciplines.
#- Perhaps the oldest through its inclusion of astronomy.
#- Over the last two millennia.
#  Physics was a part of natural philosophy along with chemistry.
#+ Quantum chemistry is a branch of chemistry.