编写一个脚本包装3个python代码

Question

我有3个python代码，我想一个接一个地自动调用，这样它们就可以在s单次调用中得到最终结果。 如何将这些代码包装成单个脚本？代码是model-multiple.py，align2d.py，model-single.py。在

型号-多个.py是

from modeller import *              # Load standard Modeller classes
from modeller.automodel import *    # Load the automodel class

log.verbose()    # request verbose output
env = environ()  # create a new MODELLER environment to build this model in


env.io.atom_files_directory = ['.', '../atom_files']

a = automodel(env,
alnfile  = '3NTD_align.ali', # alignment filename
knowns   = ('3NTDA'),    
sequence = 'target',        # code of the target
assess_methods=(assess.DOPE, assess.GA341,assess.normalized_dope))
a.starting_model= 1                 # index of the first model
a.ending_model  = 1              # index of the last model
                                    # (determines how many models to calculate)
a.make()                            # do the actual homology modeling

Answer 1

您有两种选择：

1. 快速而肮脏的方法：在shell脚本或Python脚本中逐个调用它们（使用system或{}）
2. 让它们在某个函数中工作，将它们导入到单个脚本中，并调用每个模块的“do work”函数