擅长:python、mysql、java
<p>我认为你走错路了。如果可以对其进行加扰,则只需检查每个字符的计数是否相同。在javascript中,可以执行以下操作:</p>
<p/><div^{cl1}$&13;
<div^{cl2}$&13;
<pre class="snippet-code-js lang-js prettyprint-override"><code>function isRepeating(str) {
var characters = str.split('');
if (characters.length < 2) { return false; }
var characterCounts = characters.reduce(function(carry, char) {
carry[char] = carry[char] ? carry[char] + 1 : 1;
return carry;
}, {});
var counts = Object.values(characterCounts);
return !counts.some(c => c !== counts[0]);
}
console.log(isRepeating("123a123a321a")); // true
console.log(isRepeating("hello")); // false
console.log(isRepeating("racecar")); // false
console.log(isRepeating("raceecar")); // true</code></pre>
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</div>和13;
</div>和13;
<p>对于python,只需遵循相同的方法-计数每个字符出现的次数,看看每个字符是否具有相同的计数。在</p>