我有大量的产品描述数据,需要将产品名称和意图与描述分开,我发现在用POS标记标记文本之后分离NNP标记对进一步清理有一定帮助。在
我有以下类似的数据,我只想过滤NNP标记,并希望它们在各自的列表中被过滤,但不能这样做。在
data = [[('User', 'NNP'),
('is', 'VBZ'),
('not', 'RB'),
('able', 'JJ'),
('to', 'TO'),
('order', 'NN'),
('products', 'NNS'),
('from', 'IN'),
('iShopCatalog', 'NN'),
('Coala', 'NNP'),
('excluding', 'VBG'),
('articles', 'NNS'),
('from', 'IN'),
('VWR', 'NNP')],
[('Arfter', 'NNP'),
('transferring', 'VBG'),
('the', 'DT'),
('articles', 'NNS'),
('from', 'IN'),
('COALA', 'NNP'),
('to', 'TO'),
('SRM', 'VB'),
('the', 'DT'),
('Category', 'NNP'),
('S9901', 'NNP'),
('Dummy', 'NNP'),
('is', 'VBZ'),
('maintained', 'VBN')],
[('Due', 'JJ'),
('to', 'TO'),
('this', 'DT'),
('the', 'DT'),
('user', 'NN'),
('is', 'VBZ'),
('not', 'RB'),
('able', 'JJ'),
('to', 'TO'),
('order', 'NN'),
('the', 'DT'),
('product', 'NN')],
[('All', 'DT'),
('other', 'JJ'),
('users', 'NNS'),
('can', 'MD'),
('order', 'NN'),
('these', 'DT'),
('articles', 'NNS')],
[('She', 'PRP'),
('can', 'MD'),
('order', 'NN'),
('other', 'JJ'),
('products', 'NNS'),
('from', 'IN'),
('a', 'DT'),
('POETcatalog', 'NNP'),
('without', 'IN'),
('any', 'DT'),
('problems', 'NNS')],
[('Furtheremore', 'IN'),
('she', 'PRP'),
('is', 'VBZ'),
('able', 'JJ'),
('to', 'TO'),
('order', 'NN'),
('products', 'NNS'),
('from', 'IN'),
('the', 'DT'),
('Vendor', 'NNP'),
('VWR', 'NNP'),
('through', 'IN'),
('COALA', 'NNP')],
[('But', 'CC'),
('articles', 'NNS'),
('from', 'IN'),
('all', 'DT'),
('other', 'JJ'),
('suppliers', 'NNS'),
('are', 'VBP'),
('not', 'RB'),
('orderable', 'JJ')],
[('I', 'PRP'),
('already', 'RB'),
('spoke', 'VBD'),
('to', 'TO'),
('anic', 'VB'),
('who', 'WP'),
('maintain', 'VBP'),
('the', 'DT'),
('catalog', 'NN'),
('COALA', 'NNP'),
('and', 'CC'),
('they', 'PRP'),
('said', 'VBD'),
('that', 'IN'),
('the', 'DT'),
('reason', 'NN'),
('should', 'MD'),
('be', 'VB'),
('the', 'DT'),
('assignment', 'NN'),
('of', 'IN'),
('the', 'DT'),
('plant', 'NN')],
[('User', 'NNP'),
('is', 'VBZ'),
('a', 'DT'),
('assinged', 'JJ'),
('to', 'TO'),
('Universitaet', 'NNP'),
('Regensburg', 'NNP'),
('in', 'IN'),
('Scout', 'NNP'),
('but', 'CC'),
('in', 'IN'),
('P17', 'NNP'),
('table', 'NN'),
('YESRMCDMUSER01', 'NNP'),
('she', 'PRP'),
('is', 'VBZ'),
('assigned', 'VBN'),
('to', 'TO'),
('company', 'NN'),
('001500', 'CD'),
('Merck', 'NNP'),
('KGaA', 'NNP')],
[('Please', 'NNP'),
('find', 'VB'),
('attached', 'JJ'),
('some', 'DT'),
('screenshots', 'NNS')]]
我写了以下代码:
^{pr2}$其输出如下:
['User',
'Coala',
'VWR',
'Arfter',
'COALA',
'Category',
'S9901',
'Dummy',
'POETcatalog',
'Vendor',
'VWR',
'COALA',
'COALA',
'User',
'Universitaet',
'Regensburg',
'Scout',
'P17',
'YESRMCDMUSER01',
'Merck',
'KGaA',
'Please']
我想得到的输出是:
[['User',
'Coala',
'VWR']
['Arfter',
'COALA',
'Category',
'S9901',
'Dummy']
[],
[],
['POETcatalog'],
['Vendor',
'VWR',
'COALA'],
[],
['COALA'],
['User',
'Universitaet',
'Regensburg',
'Scout',
'P17',
'YESRMCDMUSER01',
'Merck',
'KGaA'],
['Please']]
还试图使用[[] for i in range(len(data)]
将其附加到各自的列表中,但无法这样做。在
您可以使用以下列表理解:
输出:
^{pr2}$列表理解是一种方法。但是@麦迪的回答可能有点难以理解。在
下面是一个更易于阅读的解决方案:
如果您喜欢更简洁的代码,并且可以围绕嵌套列表理解进行思考,https://stackoverflow.com/a/3633145/610569:
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