使用python urllib2发送POST请求并获取响应

2024-05-23 13:33:39 发布

您现在位置:Python中文网/ 问答频道 /正文

我正在尝试从发送POST请求中获取HTML页面:

import httplib 
import urllib 
import urllib2 
from BeautifulSoup import BeautifulSoup


headers = {
    'Host': 'digitalvita.pitt.edu',
    'Connection': 'keep-alive',
    'Content-Length': '325', 
    'Origin': 'https://digitalvita.pitt.edu',
    'User-Agent': 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_7_4) AppleWebKit/537.1 (KHTML, like Gecko) Chrome/21.0.1180.89 Safari/537.1',
    'Content-type': 'application/x-www-form-urlencoded; charset=UTF-8',
    'Accept': 'text/javascript, text/html, application/xml, text/xml, */*',
    'Referer': 'https://digitalvita.pitt.edu/index.php',
    'Accept-Encoding': 'gzip,deflate,sdch',
    'Accept-Language': 'en-US,en;q=0.8',
    'Accept-Charset': 'ISO-8859-1,utf-8;q=0.7,*;q=0.3',
    'Cookie': 'PHPSESSID=lvetilatpgs9okgrntk1nvn595'
}

data = {
    'action': 'search',
    'xdata': '<search id="1"><context type="all" /><results><ordering>familyName</ordering><pagesize>100000</pagesize><page>1</page></results><terms><name>d</name><school>All</school></terms></search>',
    'request': 'search'
}

data = urllib.urlencode(data) 
print data 
req = urllib2.Request('https://digitalvita.pitt.edu/dispatcher.php', data, headers) 
response = urllib2.urlopen(req)
the_page = response.read()

soup=BeautifulSoup(the_page)
print soup

有人能告诉我怎么做吗?


Tags: texthttpsimportsearchdatapagecontenturllib2
1条回答
网友
1楼 · 发布于 2024-05-23 13:33:39

不要指定Content-Length头,urllib2会为您计算它。实际上,您的头指定了错误的长度:

>>> data = urllib.urlencode(data) 
>>> len(data)
319

如果没有这个头,剩下的代码就可以正常工作了。

相关问题 更多 >