Django 1.6名称选择未定义

Question

我试图在我的模板中显示一个下拉菜单，但我得到以下错误

File "forms.py" in DropdownSelectionForm
  101.     selection = forms.ChoiceField(choices=MY_CHOICES, widget = Select)

Exception Type: NameError at /
Exception Value: name 'Select' is not defined

这是我要展示表单的模板

^{pr2}$

给你表单.py在

MY_CHOICES = (
    ('Dermatologist', 'Dermatologist'),
    ('Dentist', 'Dentist'),
    ('Opthalmologist', 'Opthalmologist'),
)

class DropdownSelectionForm(forms.Form):
    selection = forms.ChoiceField(choices=MY_CHOICES, widget = Select)

Answer 1

Python找不到Select，我看到你已经导入了django.forms，所以试试widget=forms.Select

Answer 2

像Python中的其他任何东西一样，您需要正确地引用对象。在本例中，Select是通过forms模块提供的，与ChoiceField完全相同。在

selection = forms.ChoiceField(choices=MY_CHOICES, widget=forms.Select)