通过SleekXMPP发送facebook消息

Question

我试图用sleekXMPP在facebook聊天上发送一条消息，用这里的答案作为样板：Send a Facebook Message with XMPP using Access Tokens in Python

我的代码是

import sleekxmpp

class SendMsgBot(sleekxmpp.ClientXMPP):
    def init(self, jid, recipient, message):

        print "..."

        sleekxmpp.ClientXMPP.__init__(self, jid, 'ignore')
        self.recipient = recipient
        self.msg = message
        self.add_event_handler("session_start", self.start, threaded=True)

    def start(self, event):
        self.send_presence()
        self.get_roster()
        self.send_message(mto=self.recipient, mbody=self.msg, mtype='chat')

        self.disconnect(wait=True)



if __name__ == "__main__":
    xmpp = SendMsgBot(from_id, to_id, unicode(message))

    xmpp.credentials['apikey'] = api_key
    xmpp.credentials['accesstoken'] = o_auth_token

    if xmpp.connect(('chat.facebook.com', 5222)):
        xmpp.process(block=True)
        print("Done")
    else:
        print("Unable to connect")

但是，当我运行脚本时，我收到以下错误消息：

^{pr2}$

任何想法都将不胜感激！在

Answer 1

此外，一些重要的破折号似乎已从原始代码中删除。在

我也不得不改变

xmpp.credentials['apikey'] = api_key
xmpp.credentials['accesstoken'] = o_auth_token

到

^{pr2}$

这些显然是Facebook期望的参数名，正如您在Facebook的PHPexample中看到的那样

Answer 2

在SendMsgBot类中(sleekxmpp.ClientXMPP)：，你需要改变

def init（self，jid，recipient，message）到def init（self，jid，recipient，message）

我希望它能起作用。在