文件Java错误中的NullPointerException
我必须写一个程序,它将字母形式的分数转换成数字形式,如a、B、C、D或F(分别为4、3、2、1、0)。等级可以有+或-太多(+增加等级0.3,-减少相同数量)。 我写了这个程序:
public class Grade{
private String letterGrade;
private String letter;
private String symbol = "n";
private double numericGrade;
private double grade;
private final double PLUS = 0.3;
private final double MENO = -0.3;
public Grade(String letterGrade) {
this.letterGrade = letterGrade;
}
public double getNumericGrade() {
if (letterGrade.length() > 1) {
letter = letterGrade.substring(0, 1);
symbol = letterGrade.substring(1, 2);
}
if (letter.equals("A")) {
numericGrade = 4.0;
if (symbol.equals("+")) {
symbol = "n";
}
}
else if (letter.equals("B")) {
numericGrade = 3.0;
}
else if (letter.equals("C")) {
numericGrade = 2.0;
}
else if (letter.equals("D")) {
numericGrade = 1.0;
}
else if (letter.equals("F")) {
numericGrade = 0.0;
}
if (symbol.equals("+")) {
grade = numericGrade + PLUS;
}
else if (symbol.equals("-")) {
grade = numericGrade + MENO;
}
else {
grade = numericGrade;
}
return grade;
}
}
和程序测试仪:
import java.util.Scanner;
public class GradeTester{
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.print("Please enter the grade in letter form: ");
String letterGrade = in.next();
if (letterGrade.equals("A") || letterGrade.equals("A+") || letterGrade.equals("A-")) {
Grade graduation = new Grade(letterGrade);
System.out.println("The grade in number form is: " + graduation.getNumericGrade());
}
else if (letterGrade.equals("B") || letterGrade.equals("B+") || letterGrade.equals("B-")) {
Grade graduation = new Grade(letterGrade);
System.out.println("The grade in number form is: " + graduation.getNumericGrade());
}
else if (letterGrade.equals("C") || letterGrade.equals("C+") || letterGrade.equals("C-")) {
Grade graduation = new Grade(letterGrade);
System.out.println("The grade in number form is: " + graduation.getNumericGrade());
}
else if (letterGrade.equals("D") || letterGrade.equals("D+") || letterGrade.equals("D-")) {
Grade graduation = new Grade(letterGrade);
System.out.println("The grade in number form is: " + graduation.getNumericGrade());
}
else if (letterGrade.equals("F")) {
Grade graduation = new Grade(letterGrade);
System.out.println("The grade in number form is: " + graduation.getNumericGrade());
}
else {
System.out.println("Not permissed!");
}
}
}
但当我尝试时,仅针对不带+或-的字母出现以下错误:
Exception in thread "main" java.lang.NullPointerException
at Grade.getNumericGrade(Grade.java:20)
at GradeTester.main(GradeTester.java:13)
我不明白出了什么问题
# 1 楼答案
请尝试使用
"A".equals(letter)
代替letter.equals("A")
以防止空指针,因为“A”永远不能为空:-)您可能希望对all equals()执行此操作,首先是常量,然后是变量,然后重试您的代码
oh和
Grade
中的letter
始终是null
,因为它仅在同时给出符号时设置只是因为我觉得很慷慨:-)这里有一个工作版本