2024-03-29 15:29:48 发布
网友
我有一个字符串列表
a = ['word1, 23, 12','word2, 10, 19','word3, 11, 15']
我想创建一个列表
b = [['word1',23,12],['word2', 10, 19],['word3', 11, 15]]
这样做容易吗?
试试这个:
b = [ entry.split(',') for entry in a ] b = [ b[i] if i % 3 == 0 else int(b[i]) for i in xrange(0, len(b)) ]
input = ['word1, 23, 12','word2, 10, 19','word3, 11, 15'] output = [] for item in input: items = item.split(',') output.append([items[0], int(items[1]), int(items[2])])
比其他人更简洁:
def parseString(string): try: return int(string) except ValueError: return string b = [[parseString(s) for s in clause.split(', ')] for clause in a]
或者,如果您的格式被固定为<string>, <int>, <int>,那么您可以更加简洁:
<string>, <int>, <int>
def parseClause(a,b,c): return [a, int(b), int(c)] b = [parseClause(*clause) for clause in a]
试试这个:
比其他人更简洁:
或者,如果您的格式被固定为
<string>, <int>, <int>
,那么您可以更加简洁:相关问题 更多 >
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