有没有方法可以删除字符串中重复和连续的单词/短语？

Question

有没有方法可以删除字符串中重复和连续的单词/短语？E、 g

[in]：foo foo bar bar foo bar

[out]：foo bar foo bar

我试过了：

>>> s = 'this is a foo bar bar black sheep , have you any any wool woo , yes sir yes sir three bag woo wu wool'
>>> [i for i,j in zip(s.split(),s.split()[1:]) if i!=j]
['this', 'is', 'a', 'foo', 'bar', 'black', 'sheep', ',', 'have', 'you', 'any', 'wool', 'woo', ',', 'yes', 'sir', 'yes', 'sir', 'three', 'bag', 'woo', 'wu']
>>> " ".join([i for i,j in zip(s.split(),s.split()[1:]) if i!=j]+[s.split()[-1]])
'this is a foo bar black sheep , have you any wool woo , yes sir yes sir three bag woo wu'

当它变得更复杂一点，我想删除短语（比如短语最多可以由5个单词组成）时会发生什么？怎么能做到呢？E、 g

[in]：foo bar foo bar foo bar

[out]：foo bar

另一个例子：

[in]：this is a sentence sentence sentence this is a sentence where phrases phrases duplicate where phrases duplicate . sentence are not prhases .

[out]：this is a sentence where phrases duplicate . sentence are not prhases .

Answer 1

就我个人而言，我不认为我们需要为此使用任何其他模块（尽管我承认其中一些模块非常棒）。我只是通过简单的循环来管理这个问题，首先将字符串转换成一个列表。我在上面列出的所有例子上都试过了。它工作得很好。在

sentence = str(raw_input("Please enter your sentence:\n"))

word_list = sentence.split()

def check_if_same(i,j): # checks if two sets of lists are the same

    global word_list
    next = (2*j)-i   # this gets the end point for the second of the two lists to compare (it is essentially j + phrase_len)
    is_same = False
    if word_list[i:j] == word_list[j:next]:

        is_same = True
        # The line below is just for debugging. Prints lists we are comparing and whether it thinks they are equal or not
        #print "Comparing: " + ' '.join(word_list[i:j]) + " " + ''.join(word_list[j:next]) + " " + str(answer)

    return is_same

phrase_len = 1

while phrase_len <= int(len(word_list) / 2): # checks the sentence for different phrase lengths

    curr_word_index=0

    while curr_word_index < len(word_list): # checks all the words of the sentence for the specified phrase length

        result = check_if_same(curr_word_index, curr_word_index + phrase_len) # checks similarity

        if result == True:
            del(word_list[curr_word_index : curr_word_index + phrase_len]) # deletes the repeated phrase
        else:
            curr_word_index += 1

    phrase_len += 1

print "Answer: " + ' '.join(word_list)