Python2 while循环在第二次迭代中失败

Question

我创建了一个程序，要求用户猜测温度（空间温度），然后计算该温度的黑体光谱，并返回测量数据的均方根偏差。然后要求用户再次猜测：

以下是键入的代码，因为我还不能嵌入图像：

while True:
  temperature_guess = input("What is the temperature of the black body spectrum of space (in kelvin)?\
  Type 'stop' when you're happy with your estimate.")

  if temperature_guess == "stop":
    break

  else:
    T_guess = float(temperature_guess)

    print T_guess

    # Calculate intensities produced from measured wavelengths and user guess temperature

    intensities_guess=radiation(measured_lambda_metres,T_guess)

    print intensities_guess

    # Calculate root mean square deviation from measured values

    rmsd = rmsd(measured_intensity, intensities_guess)

    print "For your guessed temperature of" , T_guess , "kelvin, \
    the root mean square deviation from measured intensity data is" , "%.4g" %rmsd , \
    "to 4 significant figures."

程序在一次迭代（一个温度猜测）中运行良好，如果我告诉它停止，程序会很好地中断，但是如果我输入另一个温度，程序会在中途暂停。我可以从打印命令中看到，它接受温度输入并根据该输入计算强度，但均方根偏差计算失败

不知何故，“rmsd”函数不喜欢它在第二次运行时看到的内容。为什么会这样？为什么要停在中间呢？

Answer 1

您似乎正在用其返回值覆盖rmsd函数。在循环中使用不同的变量名，则不会出现此问题：

while True:
    # ...

    rmsd_value = rmsd(...)   # don't do rmsd = ... here, or you overwrite the function!

    # ...