如何在Python列表中每2个元素之后添加值？

Question

我想在列表中的每两个元素之后添加一个特定的值。 例：

zz = ['a','b','c','d','f']

我想加上“英雄”一词，最终的外观将是：

zz = ['a','b','Hero','c','d','Hero','f']

我尝试使用函数insert将值放入特定索引中，但不起作用这是我的代码：

zz = ['a','b','c','d','f']
count = 0
for x in zz:
    if count == 2:
        zz.insert(count,"Carlos")
    print(x)
    count+=1

我认为这离解决方案还很远，我还是python新手

Answer 1

您可以试试这个：

letters = ['a','b','c','d','f']
n = 2
word = 'Hero'
val_list = [x for y in (letters[i:i+n] + [word] * (i < len(letters) - n) for i in range(0, len(letters), n)) for x in y]

print(val_list)

Here, used nested comprehensions to flatten a list of lists([item for subgroup in groups for item in subgroup]), sliced in groups of n with word added if less than n from end of list.

另一种选择：

letters = ['a','b','c','d','f']
n = 2
word = 'Hero'

for i in range(n, len(letters) + n, n + 1):
    letters.insert(i, word)

print ( letters )

输出：

['a', 'b', 'Hero', 'c', 'd', 'Hero', 'f']