df:
Item_Key Item_Name Delivery_Partner Ex_Delivery_Partner
10001 Brush zen zen and company
10002 sandle randv randv ltd
10003 chemical ABC zen and company
10004 chair hank hank solution
10005 shoes zen tour and zen ltd
10006 shoes XYZ tour and zen ltd
10007 ropes delv.com delv.com
10008 ropes hans ltd delv.com and Enterprises
输出:
Item_Key Item_Name Delivery_Partner Ex_Delivery_Partner
10001 Brush zen zen and company
10002 sandle randv randv ltd
10003 chemical zen zen and company
10004 chair hank hank solution
10005 shoes zen tour and zen ltd
10006 shoes zen tour and zen ltd
10007 ropes delv.com delv.com
10008 ropes delv.com delv.com and Enterprises
我需要通过在“Ex_Delivery_Partner”中选中名称来替换“Delivery_Partner”名称。 如果没有字符串匹配,则替换为“Ex_Delivery_Partner”
通过^{} 或列表理解中的} 或^{} 设置新值:
in
语句测试两个列之间的成员关系,然后通过^{相关问题 更多 >
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