Python在我运行此代码时给出了一个错误,并且我已经检查了多次。这里的源是麦克风,但它一直在询问“源”的值。我该怎么办。我应该向“源”传递什么参数
import pyttsx3
import speech_recognition as sr
#Required Modules
engine = pyttsx3.init()
r = sr.Recognizer
#Initializes variable (Avoiding Time Delay)
def Speak(audio):
engine.say(audio)
engine.runAndWait()
#Defining the function Speak() for Audio Output
def Listen():
with sr.Microphone() as source:
r.adjust_for_ambient_noise
print("Listening")
voice = r.listen(source)
print("Done Listening")
a = r.recognize_google(voice)
a = a.lower()
print("You asked - "+a)
#Defining the function Listen() for Audio Input (INTERNET REQUIRED)
while True:
Speak("Ask Me Some Questions")
#Speaks
Listen()
#Listens
try:
if a == "how are you":
print("I'm Fine Sir")
Speak("I'm Fine Sir")
#Tries to do the program without error
except:
print("Error Occured!!!")
#If error occured, this will be the Output
#Looped
这个代码给出了一个错误
Traceback (most recent call last):
File "c:\Users\Vishal\AppData\Local\Programs\Python\Python39\Python Projects\Speech.py", line 29, in <module>
Listen()
File "c:\Users\Vishal\AppData\Local\Programs\Python\Python39\Python Projects\Speech.py", line 18, in Listen
voice = r.listen(source)
TypeError: listen() missing 1 required positional argument: 'source'
实际错误是什么?如何解决?(我是python的初学者,所以对我放松点)
这是更新后的代码
1.您必须首先查看文档,应该有高级识别器()
2.如果您正在创建方法,那么对于交互,您应该返回值
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