我试着制作一副牌,然后取出2 x 2并返回结果。 我希望避免“索引外”错误。 但我一直在讨论“typeError:objectoftype'NoneType'没有len()”错误。 正如我在这里检查的,它主要来自函数用法,原因是命令查询原则, 但我不认为这会发生在这里
***代码***
def deck_creator():
suits = ("Hearts", "Diamonds", "Clubs", "Spades")
values = ("A", "2", "3", "4", "5", "6", "7", "8", "9", "10", "J", "Q", "K")
deck = []
for suit in suits:
for value in values:
card = value + " of "+ suit
deck.append(card)
return deck
def card_dealer(deck):
"""
5. Deal two cards to the Dealer and two cards to the Player
"""
print(type(deck)) # ==> !!! <class 'list'> !!!
print(len(deck)) # ==> !!! 52 !!!
dealers_cards = []
players_cards = []
shorter_then_two = True
while shorter_then_two == True:
if len(dealers_cards) < 2 or len(players_cards) < 2 :
card_number = random.randint(1, (len(deck) + 1)) # typeError: object of type 'NoneType' has no len()
card = deck[card_number]
if len(dealers_cards) < 2:
dealers_cards.append(card)
else:
players_cards.append(card)
deck = deck.remove(card)
else:
shorter_then_two = False
return players_cards, dealers_cards
a = deck_creator()
# print(a)
b = card_dealer(a)
# print(b)
结果:
card_number = random.randint(1, (len(deck) + 1))
TypeError: object of type 'NoneType' has no len()
<class 'list'>
52
我真的搞不清楚甲板列表在哪里变成了非类型对象。 谢谢你的帮助
在第一个if卡商方法声明中,您将出现错误。 从列表中删除卡时,必须执行以下操作:
您的操作方式将重新分配列表。 remove()不返回任何值(不返回任何值)
从列表中删除时,只需遵循我提到的第一种方法
这是因为您正在将值赋回
deck
变量,但list.remove(index)
返回None
,而不是更改列表相关问题 更多 >
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